Set A has a peak at 5. It is also skewed to the right. The center is 5.
Set B also has a peak at 5. Is relatively symmetrical. The center is also 5.
(Sorry about those circle in the back of my picture)
Any solution to this?
2 answers:
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Answer:
BC ≈ 4.85 m
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos26° = =
=
( cross- multiply )
5.4 × cos26° = BC , then
BC ≈ 4.85 m ( to 3 s f )
Answer:
Step-by-step explanation:
question no . 5
ratio of angle L
take angle as reference angle
using cos rule
cos L = base / hypotenuse
= 4/5
ratio of angle N
take angle N as reference angle
using sin rule
sin N = opposite / hypotenuse
= 4/5
for measure of angle L
cos L = 4/5
cos L = 0.8
L =
L = 36.9
for meanure of angle N
sin N = 4/5
sin N = 0.8
N =
N = 53.1