The first blank is propyl 4 and the second is 2 (this is what I can tell if AB was 9 then PQ 3, so practically dividing by 3)
Answer:
x = 7
Length = 4 inches , Width = 15 inches
Step-by-step explanation:
<em>PART</em><em> </em><em>1</em><em> </em><em>:</em>
Area of rectangle = Length × Width
A = L × W
L = x - 3
W = x + 8
Therefore:
A = L × W
60 = ( x - 3 ) ( x + 8 )
( x - 3 ) ( x + 8 ) - 60 = 0
x^2 + 8x - 3x - 24 - 60 = 0
x^2 + 5x - 84 = 0
x^2 + 12x - 7x - 84 = 0
x ( x + 12 ) - 7 ( x + 12 ) = 0
( x + 12 ) ( x - 7 ) = 0
THEREFORE:
x = - 12 , x = 7
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<em>PART</em><em> </em><em>2</em><em> </em><em>:</em>
L = x - 3
L = ( - 12 ) - 3
L = - 15
OR
L = ( 7 ) - 3
L = 4
THEREFORE:
Length can not be a negative number. Hence, L can not equal to - 15.
L = 4 inches
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W = x + 8
W = ( 7 ) + 8
THEREFORE:
W = 15 inches
First: Please use the symbol " ^ " to indicate exponentiation. Your f(x) should be x^2, not x2. "x^2" reads "the square of x."
Let y equal g(x) = f(x) + k: y = <span>g(x) = f(x) + k. See that "k" is a y value?
If k=1, we merely translate the graph of f(x)=x^2 UP one scale division to obtain the graph of g(x) = f(x) + 1.
So, how does the range of g(x) compare to the range of f(x)? </span>
Answer:
(3, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
3x + y = 10
y = x - 2
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute: 3x + (x - 2) = 10
- Combine like terms: 4x - 2 = 10
- Isolate <em>x </em>term: 4x = 12
- Isolate <em>x</em>: x = 3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x - 2
- Substitute in <em>x</em>: y = 3 - 2
- Subtract: y = 1
And we have our answer!
Answer:
4 over 5
Step-by-step explanation:
The simplist form of 8/10 is 4/5.