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kompoz [17]
4 years ago
14

6[7^2+3(2-12)*2]+(2*4)^2

Mathematics
1 answer:
Helen [10]4 years ago
7 0
This is what I got, hope it helps

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Find the total area for the regular pyramid.<br><br><br><br> T. A. =
Allisa [31]
The total area is:
 A = Ab + Al
 Where,
 Ab: base area
 Al: lateral area
 We have then:
 For the base area:
 Ab = (2) * (2)
 Ab = 4 units ^ 2
 For the lateral area:
 Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
 Al = (4) * (root (1 + 9))
 Al = 4raiz (10) units ^ 2
 Total area:
 A = 4 + 4raiz (10)
 Answer:
 
A = 4 + 4raiz (10)
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Fox2110Which quadratic function is represented by the table?o f(x) -3x2 2x 5f(x) 2x2 -2x 5
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B) f(x) = 3x^2 -2x + 5
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Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 56 : 48
dangina [55]

Answer:

7/6

Step-by-step explanation:

divide both the numerator and denominator by 8

3 0
3 years ago
-*~…First Answer Gets Brainliest…~*-
My name is Ann [436]

Answer:

Step-by-step explanation:

You could also use increments of 4 degrees instead, so the first line to the right of the zero point represents 4 degrees Celsius, the second represents 8 degrees and so on. Having each line represent 4 degrees is useful, since the temperatures where Celsius and Fahrenheit correspond are multiples of 4 in both scales. It's ok if you give brainliest to the other person who answered first

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3 years ago
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
4 years ago
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