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3 years ago

DOES SOMEONE UNDERSTAND???

Mathematics

1 answer:

Vlad1618 [11]3 years ago

4 0

Answer:

g(x) = 1: 0

g(-2) = -3

Step-by-step explanation:

Just by looking at the graph, at the origin, x is 0 and g(x) is 1. Now, look at where x is -2. Below that, you see where g(-2) is because -2 REPLACED x.

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What is the equation of the graph below?

alex41 [277]

Answer:

Step-by-step explanation:

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1 year ago

A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc

Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be $2x$ .

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

$I=Prt$ , where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

$6\%=\frac{6}{100}=0.06$

$10\%=\frac{10}{100}=0.10$

Amount of interest earned from lower-yielding account: $2x(0.06)=0.12x$ .

Amount of interest earned from higher-yielding account: $x(0.10)=0.10x$ .

$0.12x+0.10x=6600$

Let us solve for x.

$0.22x=6600$

$\frac{0.22x}{0.22}=\frac{6600}{0.22}$

$x=30,000$

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be $2x\Rightarrow 2(30,000)=60,000$ .

Therefore, the man invested $60,000 at 6%.

8 0

2 years ago

255,250,245,... Find the 40th term.

Brut [27]

An=-5n+260
A40=60
So the Awnser is 60

(Hope this helped!!)

5 0

2 years ago

Find the Area of ze Trapezoid

Elina [12.6K]

A=a+b/2·h=9+4/2·3.5=22.75

Hoped I helped!

3 0

3 years ago

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles.

EastWind [94]

Answer:

The Law of Sines applies to any triangle and works as follows:

a/sinA = b/sinB = c/sinC

We are attempting to solve for every angle and every side of the triangle. With the given information, A = 61°, a = 17, b = 19, we can solve for the unknown angle that is B.

a/sinA = b/sinB

17/sin61 = 19/sinB

sinB = (19/17)(sin61)

sinB = 0.9774

sin-1(sinB) = sin-1(0.9774)

B = 77.8°

With angle B we can solve for angle C and then side c.

A + B + C = 180°

C = 180° - A - B

C = 180° - 61° - 77.8°

C = 41.2°

a/sinA = c/sinC

17/sin61 = c/sin41.2

c = 17(sin41.2/sin61)

c = 12.8

The first solved triangle is:

A = 61°, a = 17, B = 77.8°, b = 19, C = 41.2°, c = 12.8

However, when we solved for angle B initially, that was not the only possible answer because of the fact that sinB = sin(180-B).

The other angle is simply 180°-77.8° = 102.2°. Therefore, angle B can also be 102.2° which will give us different values for c and C.

C = 180° - A - B

C = 180° - 61° - 102.2°

C = 16.8°

a/sinA = c/sinC

17/sin61 = c/sin16.8

c = 17(sin16.8/sin61)

c = 5.6

The complete second triangle has the following dimensions:

A = 61°, a = 17, B = 102.2°, b = 19, C = 16.8°, c = 5.6

The answer you are looking for is the first option given in the question:

B = 77.8°, C = 41.2°, c = 12.8; B = 102.2°, C = 16.8°, c = 5.6

Step-by-step explanation:

8 0

2 years ago