Given that z is a standard normal random variable, find the value of z for each situation. a. The area to the right of z is 0.01
.
1 answer:
Answer: =1.34
Step-by-step explanation:
In standard density curve
P(Z<z) = Area left of z, P(Z>z) = area right of z.
P(Z<z) +P(Z>z) =1
Given: z is a standard normal random variable.
To find : value of z if rea to the right of z is 0.01.
i.e. P(Z>z) =0.01
P(Z<z) =1-0.01 = 0.09
from z-score table, z value for this is 1.34.
Hence, z= 1.34
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