Question

A container of beads contains: 8 red beads, 6 yellow beads, and 6 green beads. A bead will be drawn from the basket and replaced 60 times. What is the reasonable prediction for the number of times the green or red bead is drawn?

Answer 1

The answer will be 14/20 because there a total of 20 beads and 8 red beads and 6 green beads which is 14 out of 20 total beads

Answer 2

Given that there are 8 red beads, 6 yellow beads, and 6 green beads in the containder.

So total number of beads = 8+6+6=20

They want to pick only green or red bead so favorable number of beads = 8+6= 14

probability of any event is given by formula

Probability= [favorable number of outcomes]/[Total number of outcomes]

So the probability of getting green or red bead in first draw = 14/20

After each draw the drawn bead is replaced means put back into container.

In that case number of beads will be same as it was in the beginning.

So the probability of getting green or red bead in second draw = 14/20

This process repeats 60 times so the required probability

$=\frac{14}{20}*\frac{14}{20}*\frac{14}{20}*...*\frac{14}{20}$ (60 times repeatition)

$=(\frac{14}{20})^{60}$

So the final answer is $(\frac{14}{20})^{60}$ .