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alina1380 [7]
3 years ago
14

Select the correct answer.

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0

Answer:

The answer would be A. 1 1/5

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

dangina [55]3 years ago
6 0

Answer:

Step-by-step explanation:

d

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The sum of two numbers is a hundred one number is at least 16 more than the other number. What are the numbers? Please help
spin [16.1K]

Answer:

58 and 42.

Step-by-step explanation:

Let the 2 numbers be x and 100-x.

Also let x be the largest number, so

x ≥ 100 - x + 16     ( 'At least 16' means equal to 16 or greater than 16).

Add in x to both sides:

x + x  ≥ 100 + 16

2x ≥ 116

x ≥ 58.

But since the sum of the 2 numbers is 100,  x must be 58 and the other number is 42.

3 0
3 years ago
Which pairs of angles in the figure below are vertical angles?<br> Check all that apply.
stich3 [128]

[ ISN} and {TSW} so the answer is D

8 0
2 years ago
Determine the length of AC and DE, and the value of x.
Readme [11.4K]

Answer:

n = 16, AC = 60, DE = 30

Step-by-step explanation:

DE joins the midpoints of 2 sides of the triangle and is half the length of the third side, that is

DE = \frac{1}{2} AC , substitute values

n + 14 = \frac{1}{2} (3n + 12) ← multiply both sides by 2 to clear the fraction

2n + 28 = 3n + 12 ( subtract 2n from both sides )

28 = n + 12 ( subtract 12 from both sides )

16 = n

Then

AC = 3n + 12 = 3(16) + 12 = 48 + 12 = 60

DE = n + 14 = 16 + 14 = 30

4 0
3 years ago
D = 7 mm<br> Calculate the radius of the circle.
Vikentia [17]

Answer:

r= d/2

7/2

3.5

3.5 is the answer

Step-by-step explanation:

5 0
3 years ago
A) 3.x + y = 11<br>a)<br>2x-y=4​
zaharov [31]

here's the solution,

first equation,

=》3x + y = 11

=》y = 11 - 3x

now, in second equation,

=》2x - y = 4

plugging the value of y as 11 - 3x,

=》2x - (11 - 3x) = 4

=》2x - 11 + 3x = 4

=》5x = 11 + 4

=》x = 15 ÷ 5

=》x = 3

now, plugging the value of x as 3 in equation 1

=》3x + y = 11

=》3 × 3 + y = 11

=》9 + y = 11

=》y = 2

5 0
3 years ago
Read 2 more answers
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