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IRINA_888 [86]
3 years ago
6

Someone help me plz

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
A. A. (-5,3), B. (-4,-4), C. (4, -2), D. (2,1)
b. A'. (-5,-3), B'. (-4,4), C'. (4,2), D'. (2,-1)
c. A", (5,-3), B". (4,4), C". (-4,2), D". (-2,-1)
d. They are in the opposite quadrant than before.

Hope this helps.
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What is the value of the expression 3.9 times 10^5 /1.3 times 10^2
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\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{3.9\times 10^5}{1.3\times 10^2}\implies \cfrac{3.9}{1.3}\times \cfrac{10^5}{10^2}\implies 3\times 10^5\cdot 10^{-2}\implies 3\times 10^{5-2}
\\\\\\
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5 0
3 years ago
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antiseptic1488 [7]

Answer:

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Then find x:

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5 0
3 years ago
Help please, I’m stressing and I’m going to have a mental break down
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Answer:

Step-by-step explanation:

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