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IceJOKER [234]
3 years ago
12

1) Which expression has a base with an exponent of 4?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

Number 4 has an exponent of 4.

Step-by-step explanation:

The ^ thingy is referring to an exponent. The number after that symbol is the exponent. Therefore, the last answer is the solution to this problem.

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Any suggestions or answers
ArbitrLikvidat [17]

This is a way to work it out

3 0
3 years ago
assume the substance has a half-life of 11 years and the initial amount is 126 grams.How long will it be until only 15 % remains
Mumz [18]
(126) times (1/2 to the x/11 power) = 15% times 126

(1/2) to the x/11 power = 0.15

Take the log of both sides :

(x/11) times log(1/2) = log(0.15)

Multiply both sides by 11 :

'x' times log(1/2) = 11 x log(0.15)

Divide both sides by " log(1/2) " :

x = 11 x log(0.15)/log(1/2) = <em><u>30.107 years</u></em> (rounded)

That's the time it takes for <em><u>any-size</u></em> sample of this substance
to decay to 15% of its original size.


5 0
3 years ago
Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).
spayn [35]

The Bernoulli distribution is a distribution whose random variable can  only take 0 or 1

  • The value of E(x2) is p
  • The value of V(x) is p(1 - p)
  • The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * (1- p) + 1^2 * p

Evaluate the exponents

E(x^2) = 0 * (1- p) + 1 * p

Multiply

E(x^2) = 0 +p

Add

E(x^2) = p

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Start by calculating E(x) using:

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * (1- p) + 1 * p

E(x) = p

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = p - p^2

Factor out p

V(x) = p(1 - p)

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

E(x^{79}) = \sum x^{79} * P(x)

So, we have:

E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p

Evaluate the exponents

E(x^{79}) = 0 * (1- p) + 1 * p

Multiply

E(x^{79}) = 0 + p

Add

E(x^{79}) = p

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0
2 years ago
Kiara spent $36 and had $12 left.<br><br> what percent money did she spend
Illusion [34]

Answer:

she spent 75%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HELP ASAP PLEASE!!! <br><br> What is the measure of ABC given A=25 &amp; C=135?
Nesterboy [21]

tbm queria saber essa pergunta

7 0
3 years ago
Read 2 more answers
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