A. 10 boys to 12 girls because both numbers in the given ratio have been multiplied by two 5*2=10 6*2=12. None of the other options can be simplified to the original given ratio of 5:6.
Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
9x-5, I guess, not sure, but I'm combining like terms. Hope it's right.
Answer:
• x = -4, x = 0, x = 1
Step-by-step explanation:
x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)
The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)
Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.
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Of course, your graphing calculator can answer this almost as quickly.
Answer:
Hence the carnival game gives you better chance of winning.
Step-by-step explanation:
Let the event of win be given by 1/10 in the game of rifle then the event of loose is given by 9/10
the
Odds in favor of a game are given by = P(Event)/ 1- P(Event)
Odds in favor of winning a rifle are given by = 1/10/ 1- 1/10
=1/10/9/10
=1/9
= 0.111
The probability of winning aa rifle game is 0.111
The probability of winning the carnival game is 0.15
Comparing the two probabilities 0.111:0.15
The probability of winning carnival game is greater than winning a rifle game
0.15>0.11
Hence the carnival game gives you better chance of winning.
