Mean starting salary was $93,000, with a standard deviation of $17,000. What is the 95% confidence interval for the average star
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The equation is undefined for singularity points at 0, 3, then c ≠ 0, c ≠ 3
<h3>What is the graph of the parent function (y)?</h3>The set of all coordinates (x, y) in the plane that satisfy the equation y = f(x) is the graph of the function. Suppose a function is only specified for a small set of input values, the graph of the function will only have a small number of points, in which each point's x-coordinate represents an input number and its y-coordinate represents an output number.
From the given information,
- The domain for the
is at x ≥ 0,
- The range is the set of values that the dependent variable for which the function is defined. f(x) ≥ 0.
In the second question:
Multiply by LCM
- c - (c - 3) = 3
Solve c - (c - 3) = 3: True for all c
c ≠ 0, c ≠ 3
Therefore, we can conclude that since the equation is undefined for singularity points at 0, 3, then c ≠ 0, c ≠ 3
Learn more about the graph of a function here:
#SPJ1
Answer:
c = 5√5
Step-by-step explanation:
When we have a right triangle, there is a property about its measurements that is <em>always</em> true, and its called the "Pythagorean Theorem"
First, let's understand the basic terms we use to describe the sides of a triangle:
we can call one leg "a", the other leg "b" and the slanted side "c"
("c" is also called the hypotenuse--and it's always opposite the 90-degree angle)
the pythagorean theorem:
a² + b² = c²
here, our "a" is 5, our "b" is 10 {and we don't know what c is}
let's try plugging these values into our formula:
a² + b² = c²
5² + 10² = c²
25 + 100 = c²
125 = c²
now, we know what c² is--but we want to know c,
so we must take the square root of both sides
√125 = √c²
√125 = c
now, while √125 <em>is </em>our answer, we can simplify further!
this is because 125 can be made up of 5 · 25
so,
and
we can take out the square root of 25 (5):
we write this as such:
so, in simplest radical form, c = 5√5
(√125)
hope this helps!! have a lovely day :)