Answer:
a) Area of the base of the pyramid = 
b) Area of one lateral face = 
c) Lateral Surface Area = 
d) Total Surface Area = 
Step-by-step explanation:
We are given the following dimensions of the triangular pyramid:
Side of triangular base = 6mm
Height of triangular base = 5.2mm
Base of lateral face (triangular) = 6mm
Height of lateral face (triangular) = 8mm
a) To find Area of base of pyramid:
We know that it is a triangular pyramid and the base is a equilateral triangle.


b) To find area of one lateral surface:
Base = 6mm
Height = 8mm
Using equation (1) to find the area:

c) To find the lateral surface area:
We know that there are 3 lateral surfaces with equal height and equal base.
Hence, their areas will also be same. So,

d) To find total surface area:
Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

Hence,
a) Area of the base of the pyramid = 
b) Area of one lateral face = 
c) Lateral Surface Area = 
d) Total Surface Area = 