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3 years ago

Help me I don’t understand this and I’ve been trying it for 20min

Mathematics

2 answers:

iris [78.8K]3 years ago

8 0

$9=\frac{v}{5} -17\\ \\ 9+17=\frac{v}{5}\\ \\ 26=\frac{v}{5}\\ \\ 26*5=v\\ \\ v=130$

Hope this helps!

natima [27]3 years ago

4 0

Multiply everything by 5
Then you’ll have
45=v-85
Add 85 to both sides
Then you’ll have
130=V
there you go

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How do I do 3? Thanks a bunch

Nataly_w [17]

A does

Hope that helps!

5 0

3 years ago

After 5 years, a $2,450 investment is worth $3,123.75.

kondaur [170]

Answer:

5.5%

Step-by-step explanation:

To solve this problem we can use a modified version of the simple interest formula which is shown below:

$r=\frac{I}{Pt}$

I = interest amount

P = principal amount

t = time (years)

The first step is to find the interest gained from the investment.

$3,123.75-2,450=673.75$

Next, plug in the values into the equation:

$r=\frac{673.75}{(2,450)(5)}$ Multiply the bottom values

$r=\frac{673.75}{12,550}$ Divide the values

$r=.055$

The last step is to convert 0.055 into a percent:

$0.055(100)=5.5$

The interest rate is 5.5%

3 0

3 years ago

According to psychologists, IQs are normally distributed, with a mean of 100 and a standard deviation of 15 . a. What percenta

Angelina_Jolie [31]

Answer: 34%.

By definition of normal distribution, ≈68% of the data is within 1 standard deviation of the mean. Therefore 68% of IQs are between 85 and 115, and half of that is on the lower end, 85 to 100.

3 0

3 years ago

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

Step-by-step explanation:

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

4 years ago

Gina has 1200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed ar

Alekssandra [29.7K]

We know the perimeter formula would be 1200=2x+2y. And the area will be A=x*y
We can to take the derivative of the area formula to find where it is a max but we must first substitute something in from the first formula so we only have one variable.

1200-2x=2y
600-x=y

A=(x)*(600-x)
A=600x-x^2

Now we take the derivative:
A'=600-2x (set equal to 0 and solve)
0=600-2x
2x=600
x=300

Then when we plug this into the perimeter formula, we can solve for y
1200=2x+2y
1200=2(300)+2y
1200=600+2y
600=2y
y=300

So both the length and width are 300 yards, and the area would be 90,000 square yards

Hope this helps

8 0

4 years ago