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3 years ago

Solve 2p^2 - 3p - 2 by factoring

Mathematics

2 answers:

elena55 [62]3 years ago

8 0

Answer: (2p+1)(p−2)

It's out of B or C.

viva [34]3 years ago

4 0

Answer:

Step-by-step explanation:

To solve by factoring equate the expression to zero, that is

2p² - 3p - 2 = 0

Consider the factors of the product of the p² term and the constant term which sum to give the coefficient of the p- term.

product = 2 × - 2 = - 4 and sum = - 3

The factors are - 4 and + 1

Use these factors to split the p- term

2p² - 4p + 1p - 2 = 0 ( factor the first/second and third/fourth terms )

2p(p - 2) + 1(p - 2) = 0 ← factor out (p - 2) from each term

(p - 2)(2p + 1) = 0

Equate each factor to zero and solve for x

p - 2 = 0 ⇒ p = 2

2p + 1 = 0 ⇒ 2p = - 1 ⇒ p = - $\frac{1}{2}$

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