It will take 4 oil changes
y = 30X
120=30(4)
y= 15X + 60
y= 15(4) + 60
y = 60 + 60
y= 120
Answer:
14. 6 × 10^7
15. 6 × 10^14
16. 7.2 × 10^-7
17. 8.5 × 10^-2
18. 23 × 10^5, 6.9 × 10^6, 72 × 10^5
19. 1.89 × 10^-4, 2.5 × 10^-4, 19 × 10^-3
20. 3.125 × 10^-5
21. 3.1536 × 10^9
Step-by-step explanation:
14.
- (2 × 10^5)(3 × 10^2)
- (200000)(3 × 10^2)
- (200000)(300)
- 60000000
- 6 × 10^7
15.
- (1.5 × 10^5)(4 × 10^9)
- (150000)(4 × 10^9)
- (150000)(4000000000)
- 6e + 14
16.
- (6 × 10^-4)(1.2 × 10^-3)
- (0.0006)(1.2 × 10^-3)
- (0.0006)(0.0012)
- 7.2e-7
- 7.2 × 10^-7
17.
- (5 × 10^3)(1.7 × 10^-5)
- (5000)(1.7 × 10^-5)
- (5000)(0.000017)
- 0.085
- 8.5 × 10^-2
18.
- 72 × 10^5 = 7200000
- 6.9 × 10^6 = 6900000
- 23 × 10^5 = 2300000
- 23 × 10^5, 6.9 × 10^6, 72 × 10^5
19.
- 19 × 10^-3 = 0.019
- 2.5 × 10^-4 = 0.00025
- 1.89 × 10^-4 = 0.000189
- 1.89 × 10^-4, 2.5 × 10^-4, 19 × 10^-3
The ordered pair of the point I' is (-0.8, 2.4)
<h3>The complete question</h3>
Hexagon IJKLMN is shown on the coordinate plane below. If hexagon IJKLMN is dilated by a scale factor of two fifths from the origin to create hexagon I'J'K'L'M'N', what is the ordered pair of point I'?
<h3>How to evaluate the ordered pair of point I'?</h3>
From the complete question, the ordered pair of point I is given as:
I = (-2,6)
The scale factor (k) is given as:
k = 2/5
The image of the dilation is calculated using:
I' = I * k
This gives
I' = (-2,6) * 2/5
Evaluate
I' = (-0.8, 2.4)
Hence, the ordered pair of point I' is (-0.8, 2.4)
Read more about dilation at:
brainly.com/question/3457976
#SPJ1
Answer:

Step-by-step explanation:
we know that
To find out the mean change of altitude, divide the total change by the amount of time it takes
so
---> is negative because the airplane is descending
Log (base 3) x = 4 can be rewritten as:
3^4 = x
3^4 = 81
x = 81