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Natali [406]
2 years ago
9

A light-year is approximately 9.2 x 1012 kilometers. How long would it take an interstellar rocket traveling at a speed of 3,600

kilometers per hour to travel a distance of one light-year?
Mathematics
1 answer:
maw [93]2 years ago
6 0

Answer:

around 2.5 - 3 hours

Step-by-step explanation:

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Help solve this matrix question
Anna007 [38]

Answer:

The correct answer is A -6/17

7 0
3 years ago
Read 2 more answers
Z varies jointly with x, and y, and z=7 when x= 2, y= 2
fomenos

Answer:

56

Step-by-step explanation:

Complete question:

Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)

If z varies jointly with x, and y, this is expressed as;

z = kxy

If z=7 when x= 2, y= 2

7  = k(2)(2)

7 = 4k

k = 7/4

To get z when x= 4 and y = 8

z = kxy

z =7/4 (4)(8)

z = 7*8

z = 56

Hence the value of z is 56

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3 years ago
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denis-greek [22]

Answer:

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4 0
2 years ago
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True or False. <br>When multiplying two like bases, we add the exponents.
MrRissso [65]
Hi.

If I had to say, I think I would say that is True.

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7 0
3 years ago
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Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000
zvonat [6]

Answer:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

A = \int\limits^t_ {1} \,{13\cdot x^{3}}  dx

A = 13 \int\limits^t_1 {x^{3}} \, dx

A = \frac{13}{4}\cdot (t^{4}-1)

Evaluated areas are presented below:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

8 0
3 years ago
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