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Misha Larkins [42]
4 years ago
6

6 Humberto earns $7.25 per hour. If he works

Mathematics
1 answer:
mixas84 [53]4 years ago
6 0

Answer:

$8444.80 for the year

Step-by-step explanation:

7.25*22.4=162.40*52=8444.80

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125% of what number is 80?<br> Oa 36<br> Oь 40<br> Os 64<br> Od 72
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d. 72

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Answer number 14. It’s very difficult for me and i need some help.
professor190 [17]

Answer:

1201.2 in (100.1ft)

Step-by-step explanation:

A scale model represents a ratio. All sides must be shrunk or increased based on a constant value. In this case the ratio of the model is 1/13 the size of the original giving us a 1:13 ratio. So each side of your scale model must be multiplied by 13 to find the real value of the side.

First convert all units to inches then divide the width of the real windmill by the width of the scale model (both in inches) you will see the answer is 13. Multiply the inch values of all sides of your model by 13 and this gives you the proportional value of each side of the real windmill in relation to the scale model.

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3 years ago
Please help I’ll mark you as brainliest if correct
artcher [175]

Answer:

72 cm³ (see below)

Step-by-step explanation:

First, refer to the volume formula:

V = l · w · h

If you plug in all of your values and simplify, you'll get the volume:

l = 6 cm

w = 3 cm

h = 4 cm

V = (6) (3) (4)

V = 18 (4)

V = 72 cm³

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Help me plzzzz<br> I need to turn this in plz help me
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75 miles

Step-by-step explanation:

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Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

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