Volume of cylinder=πr²h volume of another cylinder=πr²h
=22/7×1.5×1.5×8 =22/7×2.5×2.5×12
=396/7 =1560/7
=56.57 =235.71
=235.71-56.57
=179.14 amount of water is able to hold by the larger cylinder
Answer:
1. -1/2
2. 3/-2
3. 1/2/2
4. 7/2
Step-by-step explanation:
Hope it helped
Answers:
- AE = 26
- AN = 58
- CT = 22.5
- Perimeter of triangle AEN = 127
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Work Shown:
Because points C, P, and T are midpoints of the sides of triangle AEN, this means the segments CP, PT, and CT are midsegments of triangle AEN.
The segment PT = 13 is a midsegment of the larger triangle, and it is parallel to the side AE. Recall the midsegment is half as long as its parallel side.
This means,
PT = (1/2)*AE
2*PT = AE
AE = 2*PT
AE = 2*13
AE = 26
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We'll use the same idea to find AN
CP = (1/2)*AN
2*CP = AN
AN = 2*CP
AN = 2*29
AN = 58
---------------
And we can also say,
CT = (1/2)*EN
CT = (1/2)*43
CT = 22.5
----------------
Add up the sides of triangle AEN to find its perimeter
Perimeter of triangle AEN = (AE)+(EN)+(AN)
Perimeter of triangle AEN = (26)+(43)+(58)
Perimeter of triangle AEN = 127
Google says. ..
Solving proportions is simply a matter of stating the ratios as fractions, setting the two fractions equal to each other, cross-multiplying, and solving the resulting equation. You'll probably start out by just solving proportions, like this: Find the unknown value in the proportion: 2 : x = 3 : 9.
Now let's do it
2. 2 is not shown in the picture
3. 2 1/2 sugar/7 1/2 flour = x sugar/1 flour
cross multiply: 2 1/2/7 1/2 = x/1
7 1/2x = 1(2 1/2) ... 15/2x = 5/2 ... x=5/2×2/15= 1/3
answer: 1/3 cup sugar = 1 cup flour ... 1/3s:1f
5. 1 1/3p/3 1/3c = ₩p/1c
cross multiply: (1 1/3)/(3 1/3) = ₩/1
3 1/3₩= 1(1 1/3) ... 10/3₩=4/3 ... ₩=4/3×3/10
₩=4/10=2/5 qt papaya
2/5 qt papaya = 1 qt carrot ... 2/5p:1c
