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Stells [14]
2 years ago
12

A sign says the distance to the next exit is 5 mi. The actual distance is 5.2 mi. To the nearest percent, what is the percent er

ror of the sign?
Mathematics
2 answers:
ivanzaharov [21]2 years ago
8 0

Answer:

About 4%

because 5 of 5.2 is about 96% so 100% - 96% = 4%

FrozenT [24]2 years ago
5 0

Answer:

4%

Step-by-step explanation:

vA = actual value

vE = expected value

percent error = ((vA - vE) / vE) x 100

((5.2 - 5) / 5) x 100 = 4

4%

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What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ?
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Read 2 more answers
Find the equation of the normal to the curve y=x^2-2x^2-4x+1 at thepoint (-1,2)​
balandron [24]

Answer:

y=-\frac{1}{3}x+\frac{5}{3}

Step-by-step explanation:

Assuming that the first exponent in the formula for the curve should be 3, not 2...

y=x^3-2x^2-4x+1

The derivative is

y'=3x^2-4x+4

The slope of the tangent line at the point (-1, 2) is the value of the derivative at x = -1.

y'|_{x=-1} = 3(-1)^2-4(-1)+4=3-4+4=3

The slope of the normal line is the opposite reciprocal of the slope of the tangent line.

m_{\text{normal} = -\frac{1}{3}

Using the Point-Slope form of a linear equation, the normal line is

y-2=-\frac{1}{3}(x-(-1))\\y-2=-\frac{1}{3}(x+1)\\y=-\frac{1}{3}x-\frac{1}{3}+2\\y=-\frac{1}{3}x+\frac{5}{3}

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2 years ago
HELP ME PLEASE!!!!!!
gladu [14]

Answer:

6x²y²

Step-by-step explanation:

6: 1 2 3 6

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36: 1 2 3 4 6 9 12 18 36

the common factor for 6 18 and 36 are

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x² = x × x

y³ = y × y × y

x³ = x × x × x

y³ = y × y × y

x³ = x × x × x

y² = y × y

the common factor are for x and y are

x² y²

Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²

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goldfiish [28.3K]

Cz I secretly enter this site

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