With digits 8, 5, and 6, an odd number must end in 5.
So far, we have _ _ 5.
The 8 is in the hundreds place.
Now we have 8_5.
The only place left for the 6 is the tens place.
The number is 865.
Answer:
Step-by-step explanation:
(2b+-7)+5(b+-3)
Multiply 5 throughout the second parentheses
(2b-7)+(5b-15)
Add 2b and 5b
7b-7-15
Subtract -7 and -15
7b-22
Answer:
I believe it would be 4/6
Step-by-step explanation:
You have four different ways to get a sum of 7: 1 and 6; 2 and 5; 3 and 4; or 4 and 3.
Answer:
(67879,96344)
Step-by-step explanation:
I took the test
