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zmey [24]
3 years ago
10

Simplify -|-28| + (-5)^2

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0
The answer is -3 because
 
-|28|= -28       now the problem looks like -28+(-5)^2

(-5)^2=25

-28 +25=  -3


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Graph a right triangle with the two points 4,5 and -4,8​
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Please write points using parentheses:  (4, 5) and (-4, 8}.

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(4, 5) is in the 1st quadrant and (-4, 8} is in the 2nd. Reversing the order of these two points yields (-4, 8) and (4, 5).  From this we can see that while moving from (-4, 8) to (4, 5) involves following a line with negative slope (because the y-coordinate decreases from 8 to 5 as the x-coordinate increases from -4 to +4).  This sloping line is the hypotenuse of a right triangle.  Draw a vertical line segment through (-4, 8) and a horizontal line segment through (4, 5).  This hypotenuse, the vertical line segment and the horizontal line segment are the boundaries of the desired right triangle.  

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3 years ago
Please help me to answer this with solution.Please answer it correctly.​
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Answer:

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8 0
3 years ago
Look at the image for the problem :)
8_murik_8 [283]

Answer:

\displaystyle V = 28 \pi \ ft^3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Volume of a Cylinder Formula: \displaystyle V = \pi r^2h

  • V is volume
  • r is radius
  • h is height

Step-by-step explanation:

<u>Step 1: Define</u>

Radius <em>r</em> = 2 ft

Height <em>h</em> = 7 ft

<u>Step 2: Solve for V</u>

  1. Substitute in variables [Volume of a Cylinder Formula]:                                \displaystyle V = \pi (2 \ ft)^2(7 \ ft)
  2. [Volume] Evaluate exponents:                                                                         \displaystyle V = \pi (4 \ ft^2)(7 \ ft)
  3. [Volume] Multiply:                                                                                             \displaystyle V = 28 \pi \ ft^3
5 0
3 years ago
A cylindrical tank with radius 3 m is being filled with water at a rate of 4 m3/min. How fast is the height of the water increas
Fittoniya [83]

Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>How to solve?</h3>

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

#V=pi r^2 h#

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

#V=pi (5m)^2 h#

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

#(dV)/(dt)=(25 m^2) pi (dh)/(dt)#

In the problem, we are given #3(m^3)/min# which is #(dV)/(dt)#.

So we need to substitute this in:

#(dh)/(dt)=(3m^3)/(min (25m^2) pi)=3/(25 pi)m/(min)#

Hence,  Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>Formula used: </h3>

#V=pi r^2 h#

To Learn more visit:

brainly.com/question/4313883

#SPJ4

4 0
2 years ago
Read 2 more answers
6h − (9−3h) = 6 − 3 (h+2) <br><br> h=3/2 <br><br> h=3/4 <br><br> h=17/6 <br><br> h=7/2
Andre45 [30]
I would try going with h =7/2 if that is wrong just rate me 1
3 0
3 years ago
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