G = {(0, 1)} Is G-1 a function and why?

Mathematics

2 answers:

frosja888 [35]3 years ago

7 0

Answer:

Yes, each element in the domain has only one range value.

Step-by-step explanation:

I know because I just took a test and got it right. ;)

Liono4ka [1.6K]3 years ago

5 0

Answer:

From the information provided you cannot conclude whether or not G-1 is a function. You would need more coordinates in the set to conclude this answer.

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Read 2 more answers

30 points 1 question PLEASE HELP ME OUT I REALLY NEED IT

Pachacha [2.7K]

Answer:

p(-5/3) ≠ 0 So, (3 x +5) is NOT A FACTOR of p(x)

Step-by-step explanation:

Here, the given function is $p(x)=3x^5+2x^2 - 5$

Now, the given root of the function is ( 3x +5)

Now, if ( 3 x + 5) = 0,

we get x = - 5/3

So, the zero of the given polynomial is x = -5/3

Then, x = -5/3, p(x) =0 ⇒ ( 3 x + 5) is a FACTOR of p(x)

Now, let us find the value of function at x = -5/3

Substitute x = -5/3 in the given function p(x), we get:

$p(x)=3x^5+2x^2 - 5 \implies p(\frac{-5}{3}) = 3(\frac{-5}{3})^5 + 2(\frac{-5}{3})^2 - 5\\= 3(\frac{-3,125}{243}) + 2(\frac{25}{9}) - 5\\= (\frac{-3,125}{81}) + (\frac{50}{9}) - 5\\= -38.580 + 5.56 - 5 = -38.02\\\implies p(\frac{-5}{3}) = -38.02$