Answer:
Step-by-step explanation:
either b or c not sure
The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
First you distribute the -12 to the (x+5) getting 144=-12x-60.
Next you add 60 to each side getting 204=-12x
Then you divide each side by -12 getting -17=x, which is the answer.<span />
Answer: Where is the question???
Step-by-step explanation:
