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Brut [27]
3 years ago
9

Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one

hazelnut chocolate box and $30 to make one almond chocolate box. It takes her 20 minutes to make either box of chocolates. She wants to spend no more than $210 and 200 minutes making the chocolate boxes to give to her friends.
If each hazelnut box contains 10 chocolates and each almond box contains 15 chocolates, how many boxes of hazelnut and almond chocolates will maximize the number of chocolates she gives to her friends?
Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

the answer is Bill Shorten

olga55 [171]3 years ago
5 0

Answer:

Samantha should make six hazelnut chocolate boxes and four almond chocolate boxes in order to maximize the number of chocolates she gives to her friends.

Step-by-step explanation:

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The easiest way is to try the point (-4,1), that is, x=-4, y=1,
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b works.

The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius. 
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2² 
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.

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VladimirAG [237]
Solution= x=5
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<span>10.
if we were to subsitute the points and graph the equation we would notice that the shape is the same for both: a 45 degree angle line that goes upleft and up right
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Sidana [21]

Answer:

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Step-by-step explanation:

...........................

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3 years ago
About 3% of children in the United States are allergic to peanuts. Choose three children at random and let the random variable X
Charra [1.4K]

Answer:

0.029991 = 2.9991% conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are allergic to peanuts, or they are not. The probability of a children being allergic to peanut butter is independent of other children. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

3% of children in the United States are allergic to peanuts.

So p = 0.03

Three children:

So n = 3,

The probabilities are:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.03)^{0}.(0.97)^{3} = 0.912673

P(X = 1) = C_{3,1}.(0.03)^{1}.(0.97)^{2} = 0.084681

P(X = 2) = C_{3,2}.(0.03)^{2}.(0.97)^{1} = 0.002619

P(X = 3) = C_{3,3}.(0.03)^{3}.(0.97)^{0} = 0.000027

What is the conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy?

This is

p = \frac{P(X = 2)}{P(X \geq 1)}

In which

P(X \geq 1) = 0.084681 + 0.002619 + 0.000027 = 0.087327

P(X = 2) = 0.002619

So

p = \frac{0.002619}{0.087327} = 0.03

0.029991 = 2.9991% conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy

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3 years ago
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