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Brut [27]
2 years ago
9

Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one

hazelnut chocolate box and $30 to make one almond chocolate box. It takes her 20 minutes to make either box of chocolates. She wants to spend no more than $210 and 200 minutes making the chocolate boxes to give to her friends.
If each hazelnut box contains 10 chocolates and each almond box contains 15 chocolates, how many boxes of hazelnut and almond chocolates will maximize the number of chocolates she gives to her friends?
Mathematics
2 answers:
zloy xaker [14]2 years ago
7 0

the answer is Bill Shorten

olga55 [171]2 years ago
5 0

Answer:

Samantha should make six hazelnut chocolate boxes and four almond chocolate boxes in order to maximize the number of chocolates she gives to her friends.

Step-by-step explanation:

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X is less than or equal to 9 and greater than or equal to 5
topjm [15]
5≤x≤9 it can also be reversed as 9≥x≥5 which is the same thing
3 0
3 years ago
Read 2 more answers
Find the sixth term of the sequence 1/2, -3/8, 9/32
sukhopar [10]

Answer:

The sixth term is -243/2048 ⇒ answer B

Step-by-step explanation:

* Lets explain the geometric sequence

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5  ,  10  ,  20  ,  40  ,  80  ,  ………………………. (×2)

# 5000  ,  1000  ,  200  ,  40  ,  …………………………(÷5)  

* General term (nth term) of a Geometric sequence:

# U1 = a  ,  U2  = ar  ,  U3  = ar²  ,  U4 = ar³  ,  U5 = ar^4

# Un = ar^(n-1), where a is the first term , r is the constant ratio

  between each two consecutive terms  and n is the position of the

  number in the sequence

- Ex: U5 = ar^4  ,  U7 = ar^6  ,  U10 = ar^9  ,  U12 = ar^11

- Lets solve the problem

∵ The sequence is 1/2 , -3/8 , 9/32

- Lets find the constant ratio r

∵ The first term is a = 1/2

∵ The second term is U2 = ar

∵ The second term  U2 = -3/8

∴ ar = -3/8

∴ 1/2 r = -3/8 ⇒ multiply both sides by 2

∴ r = -3/4

- Lets find the sixth term

∵ a = 1/2 and r = -3/4

∵ n = 6

∴ U6 = ar^5

∴ U6 = 1/2 (-3/4)^5 = 1/2 × -243/1024 = -243/2048

* The sixth term is -243/2048

8 0
3 years ago
Read 2 more answers
Farad wrote the expression 32 - 8f to represent
motikmotik
Look at this and you will be surprised on how it helps many like you that’s a key answer

7 0
2 years ago
Read 2 more answers
Could someone answer and explain these please? Thank you!
Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

x=(10 \times t)+(1 \times u)

x=10t+u

The two digit number 'y' is obtained by reversing the digits of x.

So, y=(10 \times u)+(1 \times t)

y=10u+t

Now, the value of x-y is expressed as:

x-y=(10t+u)-(10u+t)

x-y=10t+u-10u-t

x-y=9t-9u

x-y=9(t-u)

So, 9(t-u) is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = \frac{a}{1-r}

Since, the sum of the given infinite geometric series = 200

Therefore,\frac{a}{1-r}=200

Since, r=0.15 (given)

\frac{a}{1-0.15}=200

\frac{a}{0.85}=200

a=0.85 \times 200

a=170

The nth term of geometric series is given by ar^{n-1}.

So, second term of the series = ar^{2-1} = ar

Second term = 170 \times 0.15

= 25.5

So, the second term of the geometric series is 25.5






Step-by-step explanation:


8 0
3 years ago
Please help, will give brainliest
Goryan [66]
Uhhh i think the answers A
3 0
2 years ago
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