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3 years ago

Finding Domain.

1 answer:

6 0

$(f \circ g)(x)=(\sqrt{x-5})^2+2=x-5+2=x-3\\
D:x\in \mathbb{R}$

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Well we know that... $a^{-1}=\frac{1}{a^{1} }\\$ .

So... $(\frac{1}{5})^{-1}=\frac{1}{\frac{1}{5}^{1}}=5\\\\$ .

Because $5^{3}=125$ ,

$\frac{1}{5}^{-1*3}=125\\ x=-1*3=-3$

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