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riadik2000 [5.3K]
3 years ago
12

Evaluate [7] + | - 3|

Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer:

10

Step-by-step explanation:

Whenever you see those numbers in those specific brackets, it's asking for the absolute value of that number.

The absolute value is the distance from 0.

So, if you see -3 in those brackets, it's 3 because both -3 and 3 are 3 spaces from 0.

So 7 + 3 = 10.

Novosadov [1.4K]3 years ago
6 0

Answer:

=[7]+|-3| solve for the absolute value {-3 ->3}

=7+3

=10

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Please help, I am super stuck and I cant lose points<br><br> this homework is 16 points total
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Hello,

7)  A∪C={1,2,3,4,5,7,9}

8) A∩B={2,4}

C'= complement of C ={2,4,6}

9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}

10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}

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3 years ago
How many degrees are in an angle that turns through 1/3 of a circle?
Leona [35]

Hello!


We know that, in terms of radians and degrees, that an angle that turns through the entirety of a circle is 360 degrees. To find 1/3 of it, we just multiply by 1/3.


360(1/3)=120


Therefore, our answer is 120°.


I hope this helps!

6 0
3 years ago
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When using 3 six sided dice, what is the probability of getting a 1 on one die, a 2 on the other, and a 3 on the last die.
Semmy [17]

Answer:

1/6 is the probability for each event, so P of all three   = 1/(6^3)=1/216

Step-by-step explanation:

5 0
3 years ago
In the number 4105 how many significant figures​
Alekssandra [29.7K]

Answer:

There are 4 significant figures in the number 4105

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5 0
3 years ago
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plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =
ElenaW [278]

Answer with Step-by-step explanation:

We are given that

f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}

\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}

Right hand limit =RHL when x> 2

Substitute

x=2+h

\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}

=\frac{2}{4}=\frac{1}{2}

LHL=RHL=\frac{1}{2}

f(2)=1

LHL=RHL\neq f(2)

Hence, function is discontinuous at x=2

4 0
4 years ago
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