An extension of the Pythagorean Theorem results in what is the so-called "distance formula".
d^2=(x2-x1)^2+(y2-y1)^2, in this case you have points (-2,4) and (2,0) so:
d^2=(2--2)^2+(0-4)^2
d^2=4^2+(-4)^2
d^2=16+16
d^2=2*16
d=√32 units
d=√(2*16)
d=4√2 units
d≈5.66 units (to nearest hundredth of a unit)
Answer:
Step-by-step explanation:
Step-by-step explanation:
point 1 ( -7,y)
point 2 (1,13)
y = 7
Answer:
b
Step-by-step explanation:
7 times 7 = 49 minus 3 = 46
A Pythagorean triple is a set of thre integer numbers, a, b and c that meet the Pythgorean theorem a^2 + b^2 = c^2
Use Euclide's formula for generating Pythagorean triples.
This formula states that given two arbitrary different integers, x and y, both greater than zero, then the following numbers a, b, c form a Pythagorean triple:
a = x^2 - y^2
b = 2xy
c = x^2 + y^2.
From a = x^2 - y^2, you need that x > y, then you can discard options A and D.
Now you have to probe the other options.
Start with option B, x = 4, y = 3
a = x^2 - y^2 = 4^2 - 3^2 = 16 -9 = 7
b = 2xy = 2(4)(3) = 24
c = x^2 9 y^2 = 4^2 + 3^2 = 16 + 9 = 25
Then we could generate the Pythagorean triple (7, 24, 25) with x = 4 and y =3.
If you want, you can check that a^2 + b^2 = c^2; i.e. 7^2 + 24^2 = 25^2
The answer is the option B. x = 4, y = 3
