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AlekseyPX
4 years ago
11

How many miles are in a feet?

Mathematics
2 answers:
exis [7]4 years ago
7 0
5280 feet in one mile
0.000189394 miles in a foot


Tomtit [17]4 years ago
3 0
I believe you meant to ask how many feet are in a mile. There are 5280 feet in a mile
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The length of a rectangle picture frame is 2 centimeters more than twice it’s width. If the area of the frame is 364 square cent
sergeinik [125]

Answer:

Length:28 cm

Width: 13 cm

Step-by-step explanation:

Let

x ---> the length of a rectangle picture frame

y ---> the width of a rectangle picture frame

we know that

The area of a rectangle picture frame is equal to

A=xy

we have

A=364\ cm^2

so

364=xy ----> equation A

The length of a rectangle picture frame is 2 centimeters more than twice it’s width

so

x=2y+2 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (28,13)

see the attached figure

therefore

Length:28 cm

Width: 13 cm

5 0
3 years ago
How to write 20,484,163 in word form
Vlada [557]
I think it is twenty-million four hundred eighty four thousand one hundred sixty three
5 0
3 years ago
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Determine the slope of the line?​
antoniya [11.8K]

Answer:

C

Step-by-step explanation:

m=rise/run

rise is 1

run is 4

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3 0
3 years ago
How would you solve this equation? It uses logarithms.
slega [8]
\bf log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-----------------------------\\\\
2^{x+1}=5^{2x-1}\implies log(2^{x+1})=log(5^{2x-1})
\\\\\\
(x+1)log(2)=(2x-1)log(5)\implies (x+1)\cfrac{log(2)}{log(5)}=(2x-1)
\\\\\\
now\quad \cfrac{log(2)}{log(5)}\textit{ is just a constant about }0.43068

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4 0
3 years ago
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saveliy_v [14]

Answer:

After 1.5 second of throwing the ball will reach a maximum height of 44 ft.

Step-by-step explanation:

The height in feet of a ball after t seconds of throwing is given by the function  

h = - 16t² + 48t + 8 .......... (1)

Now, condition for maximum height is  

\frac{dh}{dt} = 0 = - 32t + 48 {Differentiating equation (1) with respect to t}

⇒ t = \frac{48}{32} = 1.5 seconds.

Now, from equation (1) we get

h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.

Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)

4 0
3 years ago
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