Question

Please help! 11 pts.

Answer 1

We can see that right triangle ABC has

1) leg AB, that is a side of the square X, side of the square X, AB= √25,

2) leg BC that is a side of the square Y, side of the square Y, BC = √144,

3) hypotenuse AC that is a side of the square Z, side of the square Z, AC = √169.

For right triangle we can use Pythagorean Theorem.

(leg1)² + (leg2)² = hypotenuse²

(AB)² + (BC)² = (AC)²

(√25)² + (√144)² = (√169)²

25 +144=169.

So, we have (AB)² + (BC)² = (AC)² and 25 +144=169.

Answer is D. (AB)² + (BC)² = (AC)² because 25 +144=169.

Answer 2

The Pythagorean theorem formula for a triangle is A^2 + B^2 = C^2 where A and B are the sides and C is the hypotenuse.

The sides of the triangle shown are AB and BC and the hypotenuse is AC,

so the correct answer would be:

(AB)2 + (BC)2 = (AC)2, because 25 + 144 = 169