Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
x = 9; y = 1
Step-by-step explanation:
Your simplified answer is 10 (ten)
Answer:
A the table display qualitative data, C two teachers do not wear glasses, E a total of 6 teachers were polled
Answer:
5x+4y=85-
Slope = -2.500/2.000 = -1.250
x-intercept = 85/5 = 17
y-intercept = 85/4 = 21.25000
2x+3y=41-
Slope = -1.333/2.000 = -0.667
x-intercept = 41/2 = 20.50000
y-intercept = 41/3 = 13.66667
