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GenaCL600 [577]
3 years ago
6

Let X be a continuous random variable with a uniform distribution on the interval open square brackets 0 comma 10 close square b

rackets. Find straight P open parentheses straight X less than 1 space or space straight X greater than 8 close parentheses.
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

X has PDF

f_X(x)=\begin{cases}\frac1{10}&\text{for }0\le x\le10\\0&\text{otherwise}\end{cases}

and thus CDF

F_X(x)=\begin{cases}0&\text{for }x10\end{cases}

Because X is continuous, we have

P(X8)=1-P(1\le X\le8)=1-(P(X\le8)-P(X\le1))

P(X8)=1-P(X\le 8)+P(X\le1)

P(X8)=1-F_X(8)+F_X(1)

P(X8)=1-\dfrac8{10}+\dfrac1{10}=\boxed{\dfrac3{10}}

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The sum of 8 and x is less than 23?
Charra [1.4K]

Answer:  no not less than 23

8 0
3 years ago
20. The H.M. between 2 and 8 is<br>(1 marks )​
e-lub [12.9K]

Answer as an improper fraction = 16/5

Answer as a mixed number = 3 & 1/5

Answer in decimal form = 3.2

All of those values represent the same thing, but written in a different way.

=============================================================

Explanation:

I'm assuming HM stands for Harmonic Mean in this case.

If so, then we apply the reciprocal operation to each value to get 1/2 and 1/8 (from 2 and 8 respectively).

Add up those fractions:

1/2 + 1/8 = 4/8 + 1/8 = 5/8

Now we'll divide n = 2 over that result. The n = 2 refers to the number of items in the original set.

n divide over (5/8) = 2*(8/5) = 16/5 which is the answer as an improper fraction

-----------

To convert to a mixed number, we can do the following:

16/5 = (15+1)/5

16/5 = 15/5 + 1/5

16/5 = 3 + 1/5

16/5 = 3 & 1/5

Or if you need the answer in decimal form, then using a calculator would get you 16/5 = 3.2

6 0
3 years ago
Marc showed 7 with this addition sentence 7=3+3+1. Use marc’s way to show these odd numbers with addition sentences . 5=
Doss [256]
The answer is: 5=3+1+1
3 0
3 years ago
The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditio
zzz [600]

If two events are independent, then

Pr(A\cap B)=Pr(A)\cdot Pr(B).

Use formulas for conditional probabilities:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)},\\ \\ Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr(A)}.

For independent events these formulas will be:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}=\dfrac{Pr(A)\cdot Pr(B)}{Pr(B)}=Pr(A),\\ \\ Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr(A)}=\dfrac{Pr(A)\cdot Pr(B)}{Pr(A)}=Pr(B).

Now in your case Pr(A)=x,\ Pr(B)=y and Pr(A|B)=x,\ Pr(B|A)=y, Pr(A\cap B)=x\cdot y.

This shows that the only correct choice is A.

5 0
4 years ago
Read 2 more answers
In Triangle ABC, AC is extended through C to D. If
DENIUS [597]

Answer:

X  = 5 unit

Step-by-step explanation:

Given as , ABC is a Triangle ,

AC extended to through C to D

∠BAC = 6x + 10

∠ABC = 6x - 10

∠BCD = ∠ 8x + 20

When c extended to D then , ∠BCD is an external angle

∵ <u>External angle = Sum of opposite internal angles</u>

Or ,∠BCD = ∠BAC + ∠ABC

Or, ∠ 8x + 20 = 6x + 10 + 6x - 10

Or, ∠ 8x + 20 = 12x

Or, 12x - 8x = 20

∴ 4x = 20

So, x = \frac{20}{4} = 5

Hence the value of X = 5  unit  Answer

8 0
3 years ago
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