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GenaCL600 [577]
3 years ago
6

Let X be a continuous random variable with a uniform distribution on the interval open square brackets 0 comma 10 close square b

rackets. Find straight P open parentheses straight X less than 1 space or space straight X greater than 8 close parentheses.
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

X has PDF

f_X(x)=\begin{cases}\frac1{10}&\text{for }0\le x\le10\\0&\text{otherwise}\end{cases}

and thus CDF

F_X(x)=\begin{cases}0&\text{for }x10\end{cases}

Because X is continuous, we have

P(X8)=1-P(1\le X\le8)=1-(P(X\le8)-P(X\le1))

P(X8)=1-P(X\le 8)+P(X\le1)

P(X8)=1-F_X(8)+F_X(1)

P(X8)=1-\dfrac8{10}+\dfrac1{10}=\boxed{\dfrac3{10}}

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- Previous 11.1.3 Quiz: The Pythagorean Theorem A WXY is a right triangle. √36 √18 W √18 O A. True O B. False ← PREVIOUS sta De
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Since (√36)² = (√18)²+(√18)², hence the triangle WXY is a right angle

<h3>What is Pythagoras theorem</h3>

The theorem states that the square of the hypotenuse is equal to the sum of the square of other two sides

For a triangle to be right angled, it must obey the law.

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Learn more on Pythagoras theorem here: brainly.com/question/343682

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