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4 years ago

The midpoint of AB = ([?],[ ])

Mathematics

1 answer:

3241004551 [841]4 years ago

4 0

Answer:

(0,0)

Step-by-step explanation:

$x_{m}=\frac{-2+2}{2}=0\\y_{m}=\frac{-2+2}{2}=0\\$

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How do you find this answer

AURORKA [14]

You have to find the slope and where it intercepts at

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3 years ago

Please help What is the sum of (2.3 × 10') and (5.0 x 10%) ?

lyudmila [28]

Answer:

i correct answer would be A

Step-by-step explanation:

i hope this helps

plz mark brainliest

3 0

3 years ago

Use the sum to product formula to find exact values: if cos255 - cos195 = squrtroot a/ 2 then a=

hodyreva [135]

By applying <em>trigonometric</em> expression and <em>direct</em> comparison, we conclude that a = 2 such cos 255° - cos 195° = √a / 2

<h3>How to analyze a trigonometric expression</h3>

In this question we need to simplify a <em>trigonometric</em> expression in order to find the value of a. In this case, we need to use the following formula:

$\cos \theta - \cos \xi = - 2\cdot \sin \left(\frac{\theta + \xi}{2} \right)\cdot \sin \left(\frac{\theta - \xi}{2} \right)$

Then,

cos 255° - cos 195° = - 2 · sin 225° · sin 30°

cos 255° - cos 195° = - 2 · sin (- 135°) · sin 30°

cos 255° - cos 195° = 2 · sin 135° · sin 30°

cos 255° - cos 195° = 2 · (√2 / 2) · (1/2)

cos 255° - cos 195° = √2 / 2

Then, by <em>direct</em> comparison we find that a = 2.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

8 0

2 years ago

How do I simplify (-13b-2b^3+9)-(-11b+7b^3+b^2)

mars1129 [50]

$(-13b-2b^3+9)-(-11b+7b^3+b^2)\\\\=-13b-2b^3+9-(-11b)-7b^3-b^2\\\\=-13b-2b^3+9+11b-7b^3-b^2\qquad\text{combine like terms}\\\\=(-2b^3-7b^3)-b^2+(-13b+11b)+9\\\\=\boxed{-9b^3-b^2-2b+9}$

4 0

3 years ago

3a - b; a = 4 , b = 6

mylen [45]

3a-b

3(4)-6

12-6

6

Answer:6

3 0

3 years ago