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iris [78.8K]
3 years ago
8

Write an equation of the line that passes through a pair of points (5, -2) , (4,5)

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

y = -7x + 33

Step-by-step explanation:

<u>Use the Point Slope Form:  (y - y1) = m(x - x1)</u>

<u />

<u>Step 1:  Find the Slope</u>

Slope = \frac{y2 - y1}{x2 - x1}

Slope = \frac{5 - (-2)}{4 - 5}

Slope = \frac{5 + 2}{-1}

Slope = \frac{7}{-1}

Slope = -7

<u>Step 2:  Plug into the point slope form</u>

(y - 5) = -7(x - 4)

y - 5 + 5 = -7x + 28 + 5

y = -7x + 33

Answer:  y = -7x + 33

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-4x - 6y = 6<br> 4x + 6y = -4
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Step-by-step explanation:

-4x - 6y = 6

4x + 6y = -4

To solve a system of equations, we can add the two equations and solve for one of the remaining variables -- let's try to eliminate the x variable when we add the two equations together.

Right now, there's a -4x term in the first equation, and a 4x term in the second equation, so if we add those together, we'll be able to eliminate the x variable altogether and solve for y.

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According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating
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Answer:

a) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

H_0: \mu=32.48\\\\H_a:\mu< 32.48

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565

The degrees of freedom for this sample size are:

df=n-1=65-1=64

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

<u>Critical value approach</u>

<u></u>

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

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3 years ago
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