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ioda
3 years ago
8

Which is the correct form of q(x) + r(x)/b(x) for expression 7x^4+x+14/x+2

Mathematics
1 answer:
BARSIC [14]3 years ago
4 0
<span>(7x^4+x+14)/(x+2)
</span>(7x^4+x+14)----------------------|(x+2)
-14x³+x+14-------------------------7x³-14x²+28x-55------> q(x)
28x²+x+14
-55x+14
110+14=124------------------------> r(x)
<span>
 </span>r(x)=124
b(x)=x+2
q(x)=7x³-14x²+28x-55

then
q(x) + r(x)/b(x)---------> (7x³-14x²+28x-55)+(124)/(x+2)

the answer is (7x³-14x²+28x-55)+(124)/(x+2)
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The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = f(x)/g(x)?
arlik [135]
This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.

Since g(x) is in the divisor position, it cannot equal 0.
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Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)
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3 years ago
What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

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d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

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3 years ago
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ivann1987 [24]

Step-by-step explanation:

y=-1

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y = x  - 6

-1 - 6= -7

Answer:

-7

6 0
3 years ago
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