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bixtya [17]
3 years ago
10

The Average cost of a long distance call in the USA was 31 cents per minute in 1978 and 8 cents in 2008. Find the approximate pe

rcent decrease in cost per minute for the long distance call from 1978 to 2008
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

74%

Step-by-step explanation:

We have been given that the Average cost of a long distance call in the USA was 31 cents per minute in 1978 and 8 cents in 2008.

We will use percent decrease formula to solve our given problem.

\text{Percent decrease}=\frac{\text{Initial}-\text{Final}}{\text{Initial}}\times 100\%

\text{Percent decrease}=\frac{31-8}{31}\times 100\%

\text{Percent decrease}=\frac{23}{31}\times 100\%

\text{Percent decrease}=0.741935483\times 100\%

\text{Percent decrease}=74.1935483\%

\text{Percent decrease}\approx 74\%

Therefore, there is an approximate 74% decrease in cost per minute for the long distance call from 1978 to 2008.

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The random variable X has the following probability mass function.X -1 0 2 6 7P(x) 0.3 0.1 0.3 0.2 0.1Answer the next 4 question
olga2289 [7]

Answer:

Step-by-step explanation:

Given that X has the following pdf.

x -1 0 2 6 7 Total

P(X) 0.3 0.1 0.3 0.2 0.1 1

xP(X) -0.3 0 0.6 1.2 0.7 2.2

x^2P(X) 0.3 0 1.2 7.2 4.9 13.6

     

Var(x) 13.6-2.2^2  8.76    

Std dev   2.959729717    

5) P( -1 < X ≤ 2) = P(0)+P(2)\\= 0.1+0.3=0.4

6. Find the cumulative distribution function F(x) and calculate F(3.2) =

x -1 0 2 6 7

P(X) 0.3 0.1 0.3 0.2 0.1

F(x) 0.3 0.4 0.7 0.9 1

F(3.2) = P(X<3.2) = ___F(X<6) = 0.7__________

7. E(X) = ______2.2_____

8. Var(X) = ____8.76______

3 0
3 years ago
Plzzz Help ASAP! This image shows a square pyramid what is the surface area of this square pyramid?
padilas [110]

Answer:

72\ ft^{2}

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^{2}+4[\frac{1}{2}bh]

where

b is the length side of the square base

h is the height of the triangular face

Remember that

Each lateral triangular face is a triangle 45°-90°-45°

so

h=b/2

we have

b=6\ ft

so

h=6/2=3\ ft

substitute in the formula

SA=6^{2}+4[\frac{1}{2}(6)(3)]=72\ ft^{2}

7 0
3 years ago
I’m confused on this one
sammy [17]

The angles that form similarity are those that are vertically opposite and 2 pairs that are equal because the for a Z formation.


Since <LPM = <ONM then


\dfrac{LP}{NO}=\dfrac{LM}{MO}\\ \\\dfrac{5x - 10}{4x-9}=\dfrac{16}{12} Cross multiply

12*(5x - 10) = 16*(4x - 9) Remove the brackets on both sides.

60x - 120 = 64x - 144 Subtract 60x from both sides.

- 120 = 64x - 60x - 144

-120 = 4x - 144 Add 144 to both sides.

-120 + 144 = 4x

24 = 4x Divide by 4

24/4 = x

x = 6



5 0
3 years ago
Chad has a rope that is 8 yards long. How many pieces of rope measuring 4/7 of a yard can he divide his rope into?
statuscvo [17]

Answer:

B

Step-by-step explanation:

Your answer is 28 because 4/7 turn it to a decimal and then divide 8 from it and that is how you get your answer 28.

Hope this helps:)

Pls mark brainlist

6 0
3 years ago
2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai
nasty-shy [4]

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}

\frac{1}{4} = \frac{15 + x + x}{x(15+x)}

\frac{1}{4} = \frac{15 + 2x}{x(15+x)}

Applying cross multiplication.

x^2 + 15x = 4(15 + 2x)

x^2 + 15x = 60 + 8x

x^2 + 7x - 60 = 0

Quadratic equation with a = 1, b = 7, c = -60. So

\Delta = 7^{2} - 4*1*60 = 289

x_{1} = \frac{-7 + \sqrt{289}}{2} = 5

x_{2} = \frac{-7 - \sqrt{289}}{2} = -12

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

4 0
2 years ago
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