Determine a series of transformations that would map polygon ABCD onto polygon A’B’C’D’?
1 answer:
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Answer:
Step-by-step explanation:
a = 2, b = 1, c = -3
We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.
a * c = 6 and the factors of 6 and 1 and 6, 2 and 3. Well, 6 - 1 doesn't equal 1 and neither does 6 + 1. So our factors are 3 and 2. In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1. That means that 3 is positive and 2 is negative. Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):
Group the first 2 terms together and the second 2 term together in order to factor:
and factor out what's common in each set of parenthesis.
Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with. We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same. Ours are identical: (2x + 3). That is common now, and can be factored out:
That matches your first choice
Answer:
The probability is 1/30 or 0.0333
Step-by-step explanation:
For calculating the probability we need to make a division between the number of ways in which the first boy born is named Sam and the second boy born is named Mark and the total number of ways in which the couple can name their children.
To calculate the total number of ways in which the couple can name their children, we can use the rule of multiplication as:
<u> 6 </u> * <u> 5 </u> = 30
First boy Born 2nd Boy Born
Because we have 6 options for the name of the first boy and 5 options for the name of the second boy.
Additionally, In just one option from this 30, the first boy is named Sam and the second is named Mark.
So, the probability is calculate as the division between 1 and 30 as: