Answer:
x = amount of pure acid to be added = 6.67ml
Step-by-step explanation:
George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?
let
x = amount of pure acid to be added
15% of 50 + x = 25% of 50 + x
(0.15 * 50) + x = 0.25(50 + x)
7.5 + x = 12.5 + 0.25x
Collect like terms
x - 0.25x = 12.5 - 7.5
0.75x = 5
x = 5/0.75
x = 6.6666666666666
Approximately,
x = 6.67
x = amount of pure acid to be added = 6.67ml
29) Turns is the ratio of annual amount to average amount.
Cost turns = 57,982.85/15,545 ≈ 3.73
Sales turns = 130,935.60/35,388 ≈ 3.70
30) Consider January of the following year to be month 13.
7/16 to 13/14 is 6 months less 2 days. There are 31 days in July, August, October, and December, so 4 more days than 30 days per month. The total number of days is 6*30 -2 +4 = 182
31) I = Prt = $5380×0.118333×90/360 = $159.16
Answer:what are answer choices
Step-by-step explanation:
Answer:
x-2y/x
Step-by-step explanation:
x²-4xy+4y²/x²+xy-6y²÷x²+3xy/x²+6xy+9y² = x-2y/x
