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Verdich [7]
3 years ago
14

Find the approximate value of the circumference of a circle with the given radius. Use = 3.14. Round your answer to the nearest

hundredth.
5.1 cm
Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0
The circumference of a circle:
C = 2 r π
If r = 5.1 cm:
C = 2 · 5.1 · 3.14 = 32.028 cm ≈ 32.03 cm
Answer:
The approximate value of the circumference is 32.03 cm ( rounded to the nearest hundredth ).
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COS (377= 32
Elanso [62]
The answer is c because the remaining number would be 10
4 0
3 years ago
The sum of three numbers is 104. The first number is 10 less than the second. The third number is 4 times the second. What are t
Shalnov [3]

Answer:

The numbers are 9, 19 and 76.

Step-by-step explanation:

Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.

The first number in terms of x:

x - 10

The second number in terms of x:

4x

If we add them all up, these 3 numbers in terms of x must be equal to 104, so:

x + (x - 10) + (4x) = 104 \\ x + x - 10 + 4x = 104 \\ 6x - 10 = 104 \\ 6x = 114 \\ x = 19

Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:

19 - 10 = 9

4 \times 19 = 76

The first number is 9, second number 19 and the third number 76.

6 0
3 years ago
X+16=24hvvcgcfcycdfdxfxxdgfv​
zaharov [31]

To do solve this you must isolate x. First subtract 16 to both sides (what you do on one side you must do to the other). Since 16 is being added to x, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.

x + (16 - 16) = 24 - 16

x = 8

Check:

8 + 16 = 24

24 = 24

Hope this helped!

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7 0
3 years ago
Read 2 more answers
One batch of walnut muffins uses
Sholpan [36]

Answer:

4 cups

Step-by-step explanation:

8 0
3 years ago
Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3
yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
2 years ago
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