<img src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D%20%2A%202%5Csqrt%7B3%7D" id="TexFormula1" title="4\sqrt{3} * 2\sqrt{3}" alt="4

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LiRa [457]

2 years ago

\sqrt{3} * 2\sqrt{3}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Marysya12 [62]2 years ago

5 0

Answer: 24

Step-by-step explanation:

yanalaym [24]2 years ago

4 0

Answer:

12.89

Step-by-step explanation:

use a calculator

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I<br> For what value of y does 125

Andrei [34K]

Answer:

-1/2

Step-by-step explanation:

7 0

3 years ago

Omg ty for the help<br><br>is this the correct way to solve for x?

Degger [83]

Answer:

x=6 degrees

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Yes! That's exactly right.

8x-1+58+75=180

8x+132=180

8x=48

x=6 degrees

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

BTW, brainliest would be greatly appreciated, I only need one more before I advance, thanks!

3 0

2 years ago

Consider the following system of equations. -10x2-10y2=-300 5x2+5y2=150 Which statement describes why the system has infinite so

scoundrel [369]

Answer:

The equations represent circles that result in the same graph.

Step-by-step explanation:

we have

$-10x^{2}-10y^{2}=-300$

Divide by -10 both sides

$x^{2}+y^{2}=30$ -----> equation A

This is the equation of a circle centered at origin with radius $r=\sqrt{30} \ units$

and

$5x^{2}+5y^{2}=150$

Divide by 5 both sides

$x^{2}+y^{2}=30$ -----> equation B

This is the equation of a circle centered at origin with radius $r=\sqrt{30} \ units$

equation A and equation B are equal

therefore

The system has infinite solutions, because the equations represent circles that result in the same graph.

4 0

2 years ago

The difference of x and 5 is less than 21.<br> Translate the sentence into an inequality.

Ad libitum [116K]

Answer:

x-5<21

Step-by-step explanation:

3 0

2 years ago

1) WET SURPRISE A water balloon is launched off of a patio. The path of the water

mart [117]

The function of the water balloon is an illustration of a quadratic function.

The balloon will splat on the ground after 2.5 seconds

The function is given as:

$h(t) = -6t^2 + 13t + 5$

When the balloon splats on the ground, the value of h(t) is 0.

So, we have:

$-6t^2 + 13t + 5 = 0$

Expand the expression

$-6t^2 + 15t- 2t + 5 = 0$

Factorize the above expression

$-3t(2t - 5)- 1(2t - 5 )= 0$

Factor out 2t - 5 in the 2t - 5

$(-3t - 1)(2t - 5 )= 0$

Split the equation into 2

$-3t - 1 = 0\ or\ 2t - 5= 0$

Rewrite as:

$-3t = 1\ or\ 2t = 5$

Solve for t

$t = -\frac 13\ or\ t = \frac 52$

The value of t cannot be less than 0 i.e. negative.

So, we have

$t = \frac 52$

Divide 5 by 2

$t = 2.5$

Hence, the balloon will splat on the ground after 2.5 seconds

Read more about quadratic functions at:

brainly.com/question/11631534

6 0

2 years ago