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ehidna [41]
3 years ago
15

Find vertical and horizontal asymtope for (x^2+2x-48)/x+8

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
There are none.

y=\dfrac{x^{2}+2x-48}{x+8}=\dfrac{(x+8)(x-6)}{x+8}\\\\y=x-6

The expression describes a straight line with a hole at x=-8 where it is undefined.

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10 pt
lord [1]

Answer:

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Step-by-step explanation:

Given:

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Required:

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Solution:

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Plug in the values

S.A = 2*π*7*24 + 2*π*7²

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3 years ago
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devlian [24]

Answer:

∠B ≈ 56.25°

Step-by-step explanation:

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B = cos^{-1}(\frac{5}{9} ) ≈ 56.25°

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Answer:

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Step-by-step explanation:

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