Find vertical and horizontal asymtope for (x^2+2x-48)/x+8

Mathematics

1 answer:

bonufazy [111]2 years ago

5 0

There are none.

$y=\dfrac{x^{2}+2x-48}{x+8}=\dfrac{(x+8)(x-6)}{x+8}\\\\y=x-6$

The expression describes a straight line with a hole at x=-8 where it is undefined.

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hichkok12 [17]

Answer:

It is the <em><u>second one</u></em>

Step-by-step explanation:

1st option does not include the number 2 from the equation above,

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6 0

3 years ago

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Rzqust [24]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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