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3 years ago

Find vertical and horizontal asymtope for (x^2+2x-48)/x+8

Mathematics

1 answer:

bonufazy [111]3 years ago

5 0

There are none.

$y=\dfrac{x^{2}+2x-48}{x+8}=\dfrac{(x+8)(x-6)}{x+8}\\\\y=x-6$

The expression describes a straight line with a hole at x=-8 where it is undefined.

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The Cheer Club is making a banner for your school using the design shown. The area of the yellow portion is 1 ft2. The expressio

olga nikolaevna [1]

Answer:

$Blue = \frac{8}{9}$

Step-by-step explanation:

Given

$Yellow = 1ft^2$

$Blue = 8z^{-1$

Required

Evaluate Blue when z = 9

To do this, we simply substitute 9 for z in $Blue = 8z^{-1$

$Blue = 8 * 9^{-1$

Convert indices to fraction

$Blue = 8 * \frac{1}{9}$

$Blue = \frac{8}{9}$

Hence, the blue section has an area of $\frac{8}{9}ft^2$

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3 years ago

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prohojiy [21]

Answer: 25

Step-by-step explanation: -5 x 25 + 13 = -112

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3 years ago

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Write the monomial in standard form. name it's coefficient and identify its degree.

Hunter-Best [27]

Answer:

$Standard\ Form = {3n^2} m^{-2}$

Step-by-step explanation:

Given

$\frac{2}{3m^2n} * 4.5n^3$

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

$\frac{2}{3m^2n} * 4.5n^3$

$Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}$

Split the numerator and the denominator

$Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}$

Multiply Like terms

$Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}$

Divide 9 by 3 to give 3

$Standard\ Form = \frac{3 * n^3}{m^2 * n}$

Divide n³ by n to n²

$Standard\ Form = \frac{3 * n^2}{m^2 }$

Split fraction

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$

From laws of indices;

$\frac{1}{a^n} = a^{-n}$

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$ becomes

$Standard\ Form = {3 * n^2} * m^{-2}$

Multiply all together

$Standard\ Form = {3n^2} m^{-2}$

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3 years ago

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Bezzdna [24]

Answer:

1- d

2- a

3- d

4- b

Step-by-step explanation:

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3 years ago

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An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h

LenKa [72]

The pool can hold 65.84 ft³ of water

Explanation:

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

$\frac{11}{1+\sqrt{2} } = a^2$

a² = $\frac{11}{2.42}$

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = $2(1+\sqrt{2} ) X (a)^2 X h$

$V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3$

Therefore, the pool can hold 65.84 ft³ of water

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3 years ago