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ehidna [41]
3 years ago
15

Find vertical and horizontal asymtope for (x^2+2x-48)/x+8

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
There are none.

y=\dfrac{x^{2}+2x-48}{x+8}=\dfrac{(x+8)(x-6)}{x+8}\\\\y=x-6

The expression describes a straight line with a hole at x=-8 where it is undefined.

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4 0
3 years ago
Read 2 more answers
9.99x10 ^-2 + 1.11 × 10^-2 i dont have the same scientific calculator as the one from school. Would like to verify my math is co
Rufina [12.5K]
The answer should not depend on which machine or which pencil you use to
find it.  If you work a problem two different ways and get two different answers,
then at least one of them is wrong, and there's a pretty good chance that both
of them are.

(9.99 of anything) + (1.11 of the same thing) = 11.1 of them

9.99 (x 10^-2) + 1.11 (x 10^-2) = <em>11.1 (x 10^-2)</em> .

Can we do any more with that ?

10^-2  =  1 / 10^2  =  1 / 100 .

11.1 x 10^-2  =  11.1 / 100  =  <em>0.111</em>
3 0
3 years ago
Susan wants to buy cherries for a party. She has $8.00 to spend. Cherries are $2.75/kg. How many kilograms of cherries can Susan
OLga [1]

Answer:you would have to divide $8.00/$2.75 and it would equal $2.90

Step-by-step explanation:This may help and if it does please thank me in the comments.

3 0
3 years ago
Which point-slope equation represents a line that passes through (3, –2) with a slope of negative StartFraction 4 Over 5 EndFrac
Schach [20]

Answer:

y + 2 = (-4/5)(x - 3)

Step-by-step explanation:

Your slope is -4/5.  Your line passes through (3, -2).

Applying the point slope formula, we get:

y + 2 = (-4/5)(x - 3)

5 0
3 years ago
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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.
PSYCHO15rus [73]

Answer:

in triangle BCD

relationship between base and hypotenuse is given by cos angle

cos 71=b/h

cos71=BD/BC

cos71=67/x

x=67/cos71=205.8ft.

the length of BC to the nearest tenth of a foot is 206ft.

8 0
3 years ago
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