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3 years ago

Find the ratio y:x, if 3x=11y,

Mathematics

1 answer:

Aleks [24]3 years ago

7 0

Answer:

3:11

Step-by-step explanation:

3x=11y

Rearrange to the format of the ratio.

11y = 3x

Let's find y/x. y/x is y:x.

11y = 3x

Divide both sides by 11.

11y/11 = 3x/11

y = 3x/11

NOW LET'S DIVIDE BOTH SIDES BY x TO GET x AS THE DENOMINATOR OF y.

y = 3x/11

y/x = (3x/11)/x

y/x = (3x/11) * 1/x

y/x = 3/11

Therefore, y:x = 3:11

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Step-by-step explanation:

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Step-by-step explanation: hope this helps!

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2 years ago

If the ratio of the sides of two squares is 3:1, what is the ratio of their perimeters?

Anvisha [2.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Help with trigonometry

Oksanka [162]

Answer:

○B. $\frac{\sqrt{6}}{2}$

Step-by-step explanation:

Trigonometric Identities

$\frac{y}{r} = sin\:θ$

$\frac{x}{r} = cos\:θ$

$\frac{y}{x} = tan\:θ$

$\frac{r}{x} = sec\:θ$

$\frac{r}{y} = csc\:θ$

$\frac{x}{y} = cot\:θ$

Radius Formula

${y}^{2} + {x}^{2} = {r}^{2}$

${[-\sqrt{15}]}^{2} + {[-\sqrt{10}]}^{2} = {r}^{2} → 15 + 10 = {r}^{2} → 25 = {r}^{2}\\ \\ 5 = r$

* Since we are talking about radii, we only want the NON-NEGATIVE root.

In this case, we will not be using the radius in our ratio, according to the trigonometric identity above because we are using the tangent ratio:

$\frac{\sqrt{6}}{2} = \frac{-\sqrt{15}}{-\sqrt{10}} = \sqrt{1\frac{1}{2}}$

I am joyous to assist you anytime.

4 0

3 years ago