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docker41 [41]
3 years ago
12

ABCDE is a regular pentagon.

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Part (A)

We have n = 5 sides, so the measure of any exterior angle of a regular pentagon is E = 360/n = 360/5 = 72

Each interior angle is therefore 180-E = 180-72 = 108 degrees.

---------------

Alternatively, you could use the formula below with n = 5

i = interior angle

i = 180(n-2)/n

i = 180(5-2)/5

i = 180(3)/5

i = 540/5

i = 108

---------------

<h3>Answer: 108 degrees</h3>

====================================================

Part (B)

We're told that CDF is 70 degrees. From part (A) we know that angle CDE is 108 degrees, so this must mean that angle EDF is 108-70 = 38 degrees.

Similarly, angle FEA is 85 degrees, which subtracts from angle AED to get 108 - 85 = 23 degrees. This is the measure of angle DEF.

So far we found

angle EDF = 38

angle DEF = 23

Let's call these x and y for shorthand. Let z be the missing third angle of triangle DFE.

So,

x+y+z = 180

38+23+z = 180

61+z = 180

x = 180-61

x = 119

Interior angle DFE is 119 degrees.

Note how 90 < x < 180 showing we have an obtuse angle. It is not a reflex angle because the statement 180 < x < 360 is false.

So we subtract the value of x from 360

360-x = 360-119 = 241

This is the reflex angle DFE

---------------

<h3>Answer: 241 degrees</h3>
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How do you add vectors? Add the vector &lt;3,4&gt; to the vector that goes 7 units at an angle of 2π/3.
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Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle \frac{2\pi }{3}

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∴ x = 7 cos(  \frac{2\pi }{3} )

∴ y = 7 sin(  \frac{2\pi }{3} )

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∵ sin(  \frac{2\pi }{3} ) =  \frac{\sqrt{3}}{2}

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∴ The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

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<em><u>Given </u></em><em><u>-</u></em><em><u> </u></em> AC is parallel to DE

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