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professor190 [17]
3 years ago
9

Florence works in the shipping department of a toy factory that makes radio-controlled helicopters. Small helicopters weigh 3 ki

lograms each, and are shipped in a container that weighs 20 kilograms. Large ones, on the other hand, weigh 4 kilograms apiece, and are shipped in a container that weighs 10 kilograms. If these boxes can hold a certain number of helicopters each, all of the packed containers will have the same shipping weight. What would the total weight be?
Mathematics
1 answer:
Damm [24]3 years ago
4 0

Answer:

50 kg

Step-by-step explanation:

Given that:

SMALL HELICOPTERS:

Weight of small helicopters = 3kg

Weight of shipping container = 20kg

LARGE HELICOPTERS:

Weight of large helicopters = 4kg

Weight of shipping container = 10kg

Number of helicopters each shipping container can hold = s ; all of the packed containers will have the same shipping weight

Shipping weight :

(Weight per helicopter * number of helicopter) + weight of shipping container

Shipping weight of Small helicopters :

(3kg * s) + 20

Shipping weight Large helicopters :

(4kg * S) + 10

Shipping weight of Small helicopters = shipping weight of large helicopters

3s + 20 = 4s + 10

20 - 10 = 4s - 3s

10 = s

Hence, member of shipped helicopters = 10

Total shipping weight :

(4 * S) + 10

(4*10) + 10

40 + 10 = 50kg

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Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

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