Answer:
Dimensions :
x (the longer side, only one side with fence ) = 90 ft
y ( the shorter side two sides with fence ) = 45 ft
Total fence used 45 * 2 + 90 = 180 ft
A(max) =
Step-by-step explanation: If a farmer has 180 ft of fencing to encloses a rectangular area with fence in three sides and the river on one side, the farmer surely wants to have a maximum enclosed area.
Lets call "x" one the longer side ( only one of the longer side of the rectangle will have fence, the other will be along the river and won´t need fence. "y" will be the shorter side
Then we have:
P = perimeter = 180 = 2y + x ⇒ y = ( 180 - x ) / 2 (1)
And A (r) = x * y
A(x) = x * ( 180 - x ) /2 ⇒ A(x) = (180/2) *x - x² / 2
Taking derivatives on both sides of the equation :
A´(x) = 90 - x
Then if A´(x) = 0 ⇒ 90 - x = 0 ⇒ x = 90 ft
and from : y = ( 180 - x ) / 2 ⇒ y = 90/2
y = 45 ft
And
A(max) = 90 * 45 = 4050 ft²
Answer:
the answer is A. because a 1/2 inch is 2 feet there is about 2 and 1/2 of an inch so if you add that, that will be 9 feet
Step-by-step explanation:
Let's solve your equation step-by-step.<span><span><span><span>2<span>x2</span></span>−<span>3x</span></span>−4</span>=0</span>Step 1: Use quadratic formula with a=2, b=-3, c=-4.<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(<span>−3</span>)</span></span>±<span>√<span><span><span>(<span>−3</span>)</span>2</span>−<span><span>4<span>(2)</span></span><span>(<span>−4</span>)</span></span></span></span></span><span>2<span>(2)</span></span></span></span><span>x=<span><span>3±<span>√41</span></span>4</span></span><span><span>x=<span><span>34</span>+<span><span><span><span>14</span><span>√41</span></span><span> or </span></span>x</span></span></span>=<span><span>34</span>+<span><span><span>−1</span>4</span><span>√<span>41</span></span></span></span></span>
Its B because B is the one that gives you most of the detail
Answer:
C. Home inventory
Step-by-step explanation: