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marissa [1.9K]
3 years ago
11

If the equation of a line has an undefined slope and passes through the point (1, 3), which form would be used to write the equa

tion of the line
Mathematics
1 answer:
aniked [119]3 years ago
6 0
Another version you can use is slope-intercept form.   The two above are standard and point-slope forms. First you do need to find the slope of the line based on m=(y2-y1)/(x2-x1) so for these points: (0,3) and (2,0) --> (x1, y1) and (x2, y2)x1=0y1=3x2=2y2=0 m= (0-3)/(2-0) = -3/2 Then your formula will need to look like y=mx+b where b is your y-intercept (when x=0)  Due to have the x=0 point, you are pretty much done: y=-3/2*x+3 If you do not have a (0,y) form, you can solve as follows:Write out the formula with your slope value inserted:y=-3/2*x+b Choose one of your points on your line to solve for b.  I choose (2,0):0=-3/2*2+b0=-3*1+b3=b --> b=3 

Hi Freedom;(0,3) (2,0)Slope is change-of-y divided by change-of-x...m=(y-y1)/(x-x1)m=(3-0)/(0-2)m=3/-2=-3/2Slope-intercept format is...y=mx+bm is the slope.b is the y-intercept, the value of y when x=0.y=(-3/2)x+bThe y intercept is provided as (0,3)...y=(-3/2)x+3 

(0,3) & (2,0) are the y and x intercepts, so the intercept form is x/2 + y/3 = 1. Multiply both sides by 6: 3x + 2y = 6. 

The slope of the line,m=y-y1/x-x1                             m=3-0/0-2=-3/2 The point slope form is y-y1=m(x-x1) y-0=-3/2(x-2) y=-3/2(x-2) 2y=-3x+6 3x+2y=6 

hope this helps hope i am brainliest 
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4 0
3 years ago
Please help me!!!!!!
goldfiish [28.3K]

Answer:

False, there are no solutions

Step-by-step explanation:

y = 2x+4

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The slopes are the same (2) but the y intercepts are different

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3 0
3 years ago
Read 2 more answers
8. The month of July has 31 days. What is the greatest
IgorLugansk [536]

Answer:

We know that one Saturday comes in a week there are 7 days in a week and there are 4 weeks in a month so in 7×4=28 days four Saturdays will come ,

But since July has 31 days so there is a possibility of 5 Saturdays as in the rest 2 days one can be Saturday. so theres a possibility of 5 Saturdays

3 0
2 years ago
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
3 years ago
Identify the outlier in the data set 6, 9, 3, 2, 10, 138, 13. Then, find the mean with and without the outlier. If necessary, ro
Andrews [41]
138 is the outlier since it is more than 1.5 * IQR past the third quartile of the data set.

With this upper outlier, the mean will be significantly higher. Without it, it will lower back down, so B is your answer
5 0
3 years ago
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