Another version you can use is slope-intercept form. The two above are standard and point-slope forms. First you do need to find the slope of the line based on m=(y2-y1)/(x2-x1) so for these points: (0,3) and (2,0) --> (x1, y1) and (x2, y2)x1=0y1=3x2=2y2=0 m= (0-3)/(2-0) = -3/2 Then your formula will need to look like y=mx+b where b is your y-intercept (when x=0) Due to have the x=0 point, you are pretty much done: y=-3/2*x+3 If you do not have a (0,y) form, you can solve as follows:Write out the formula with your slope value inserted:y=-3/2*x+b Choose one of your points on your line to solve for b. I choose (2,0):0=-3/2*2+b0=-3*1+b3=b --> b=3
Hi Freedom;(0,3) (2,0)Slope is change-of-y divided by change-of-x...m=(y-y1)/(x-x1)m=(3-0)/(0-2)m=3/-2=-3/2Slope-intercept format is...y=mx+bm is the slope.b is the y-intercept, the value of y when x=0.y=(-3/2)x+bThe y intercept is provided as (0,3)...y=(-3/2)x+3
(0,3) & (2,0) are the y and x intercepts, so the intercept form is x/2 + y/3 = 1. Multiply both sides by 6: 3x + 2y = 6.
The slope of the line,m=y-y1/x-x1 m=3-0/0-2=-3/2 The point slope form is y-y1=m(x-x1) y-0=-3/2(x-2) y=-3/2(x-2) 2y=-3x+6 3x+2y=6
