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3 years ago

Why is shillong rainier than kolkata

Geography

1 answer:

DochEvi [55]3 years ago

5 0

Answer:

Shillong is in a hilly area and the hills trap the monsoon winds, so that Shillong becomes rainier than Kolkata.

Explanation:

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List the three main types of optical telescopes, and describe their differences.

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What the person said of top of me is the answer

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3 years ago

Which nations are run by a prime minister?

Varvara68 [4.7K]

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Explanation: Hope it helped :)

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4 years ago

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A fault in which the hanging wall moves down relative to the footwall is a ______.

Phoenix [80]

Answer:

Option (B)

Explanation:

The fault usually refers to the planar type of fractures that occurs in the earth's crust. Those faults in which the hanging-wall (H.W) block goes down with respect to the foot-wall (F.W) block is considered as the normal fault. This type of fault occurs due to the tensional force or extensional force.

Here, the rocks move in the opposite direction. This movement of blocks results in the release of a certain amount of energy that leads to the occurrence of shallow-focus earthquakes.

Thus, the correct answer is option (B).

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3 years ago

Please answer this fast and here only

Vaselesa [24]

Answer:

1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{90,4\,cm}{\frac{1}{50000} }$

$r_{R,I} = 4520000\,cm$

$r_{R,I} = 45,2\,km$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{56,3\,cm}{\frac{1}{50000} }$

$r_{R,II} = 2815000\,cm$

$r_{R, II} = 28,15\,km$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{103,6\,cm}{\frac{1}{50000} }$

$r_{R,III} = 5180000\,cm$

$r_{R,III} = 51,8\,km$

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3 years ago

Which of the following is used as an argument to stop extracting tropical rain forest resources?

Ilia_Sergeevich [38]

Rainforest is home to around 40% to 75% biotic species. There's tremendous biodiversity in the plant life of the tropical rainforest. This is why it supports a very broad array of reptiles, birds, mammals, and invertebrates. So, to answer the question above: C.

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3 years ago

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