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3 years ago

What is the slope of a line that is parallel to the line Y= -12

Mathematics

1 answer:

Mice21 [21]3 years ago

3 0

Parallel lines have the same slope.

y = -12 has the slope m = 0.

Therefore, a line parallel to y = -12 has the slope m = 0.

The slope-intercept form: y = mx + b

m - slope, b - y-intercept

y = -12 = 0x - 12

m = 0, b = -12

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Elanso [62]

The way to use the distance formula to classify quadrilateral include:

Use the distance formula to measure the lengths of the sides.
Use the slope to check whether the sides are perpendicular and form right angles.
Use the slope to check whether the diagonals are perpendicular to each

<h3>How to illustrate the information?</h3>

The steps to calculate the perimeter and area of a polygon:

Step 1: Plot the given points on the graph.

Step 2: Connect the points and identify the figure.

Step 3: Determine lengths by counting the grid lines.

Step 4: Use a formula to calculate the perimeter and area if one exists.

Step 5: If there are no formulas for a figure, the perimeter can be calculated by summing the lengths of the sides. We might estimate the area without an area formula by counting the number of small squares enclosed.

Learn more about coordinate geometry on:

brainly.com/question/18269861

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4 0

2 years ago

The Highway Safety Department wants to study the driving habits of individuals. A sample of 41 cars traveling on the highway rev

PolarNik [594]

Answer:

58,21 ≤ μ ≤ 61,79

Step-by-step explanation:

Normal Distribution

Poputation size n = 41

Population mean X = 60

Population standard deviation σ = 7

Question is: Confidence Interval 90 % ??

As Confidence Interval is 90 % then α = 10 %

And as we are dealing with a two tail test

α/2 = 0,05

We look in Z table for values for α/2 = 0,05 and find

z(α/2) = - 1,64 and z(α/2) = 1,64

Then

Confidence Interval is

X - Zα/2 * σ/√n ≤ μ ≤ X + Zα/2 * σ/√n

60 - ( 1,64 ) * 7/√41 ≤ μ ≤ 60 + ( 1,64 ) * 7/√41

60 - 1,64 * 1,09375 ≤ μ ≤ 60 + 1,64 * 1,09375

60 - 1,79375 ≤ μ ≤ 60 + 1,79375

58,21 ≤ μ ≤ 61,79

4 0

4 years ago

A campus deli serves 300 customers over its busy lunch period from 11:30 a.m. to 1:30 p.m. A quick count of the number of custom

NeX [460]

Answer:

4 minutes

Step-by-step explanation:

There are two hours from 11:30 a.m. to 1:30 p.m

The hourly rate of service is:

$r=\frac{300}{2}=150\ customers/hour$

If the average number of customers in the system (n) is 10, the time that a customer spends in process is given by:

$t=\frac{n}{r} =\frac{10}{150}=0.06667\ hours$

Converting it to minutes:

$t= 0.066667\ hours*\frac{60\ minutes}{1\ hour}\\t=4\ minutes$

A customer spends, on average, 4 minutes in process.

7 0

4 years ago

Prove your very brainly ;)

scZoUnD [109]

Answer:

can you show what it says better its blurry

7 0

4 years ago

Read 2 more answers

Help, please.

Ray Of Light [21]

Answer:

the answer is 4 1/4 hours

Step-by-step explanation:

45+(80x2)=205+160=365

80_4=20+365=385

7 0

3 years ago

Read 2 more answers