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4 years ago

Prove your very brainly ;)

Mathematics

2 answers:

scZoUnD [109]4 years ago

7 0

Answer:

can you show what it says better its blurry

Llana [10]4 years ago

7 0

I can barely see it :/

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I do not get it can someone pls help me ill apreciate it

mina [271]

One thing, Check your multiplication and dividing situation.

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4 years ago

All of the following show the probability of rolling an odd number on a 6-sided number cube except which of the following?

AlexFokin [52]

C: 75% is the answer

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3 years ago

Read 2 more answers

HELP! I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!

Viefleur [7K]

Answer:

Step-by-step explanation:

The answer is A

6 0

3 years ago

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

4 years ago

Point M (-3, 5) is translated using this rule. (x, y) ----> (x - 1, y) What are the coordinates of M'?

Nuetrik [128]

Answer:

The coordinates of point M' are $M'(x,y) = (-4, 5)$ .

Step-by-step explanation:

According to the statement, we have the following translation rule:

$M'(x,y) = M(x,y) + (-1, 0)$ (1)

Where:

$M(x,y)$ - Original point.

$M'(x,y)$ - Translated point.

$(-1, 0)$ - Translation vector.

If we know that $M(x,y) = (-3, 5)$ , then the coordinates of the point M' are:

$M'(x,y) = (-3,5) + (-1,0)$

$M'(x,y) = (-4, 5)$

The coordinates of point M' are $M'(x,y) = (-4, 5)$ .

5 0

3 years ago