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Oxana [17]
3 years ago
14

The distances between three cities on a map are 45 miles, 56 miles, and 72 miles. Do the positions of

Mathematics
1 answer:
ollegr [7]3 years ago
6 0

Answer:

The position of the three cities do not form a right-triangle.

Step-by-step explanation:

There are three cities on a map (say A, B, and C).

Now, the distances between them are 45 miles, 56 miles, and 72 miles.

i.e. AB= 45 miles, BC= 56 miles and CA =72 miles.

If the three cities A, B, C form a right-angled triangle on the map, then applying Pythagoras Theorem AB² +BC² =AC²

or, AC= √(AB² +BC²) must be satisfied.

Now, right-hand side of the above equation =√(45²+56²) =71.84 ≠ 72 (AC)

Hence, Right-hand side ≠ Left-hand side.

Therefore, the positions of the three cities do not form a right triangle. (Answer)  

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John works two jobs. As a security guard he earns $8.50 per hour. As a landscaper he earns $14 per hour. One week John worked a
Rashid [163]

Answer:

John work as a security guard job <u>27 hours</u> and as a landscaper <u>33 hours</u>.

Step-by-step explanation:

Given:

John works two jobs.

As a security guard he earns $8.50 per hour and as a landscaper he earns $14 per hour.

One week John worked a total of 60 hours and earned $691.50.

Now, to find hours he work at each job.

Let the job of security guard be x hours.

And the job of landscaper be y hours.

So, the total hours John worked in a week:

x+y=60.

⇒ y=60-x.............( 1 )

<em>Now, the money earned by John in a week:</em>

8.50x+14y=691.50

<em>Putting the equation ( 1 ) in the place of y:</em>

⇒ 8.50x+14(60-x)=691.50

⇒ 8.50x+840-14x=691.50

<em>Moving variables on one side and the other we get:</em>

⇒ 840-691.50=14 x-8.50x

⇒148.50=5.50x

<em>Dividing both sides by 5.50 we get:</em>

⇒ 27=x

<u>As a security guard job he worked 27 hours</u><u>.</u>

Putting the value of in x equation ( 1 ) we get:

y=60-27

⇒ y=33.

<u>As a landscaper he worked 33 hours</u>.

Therefore, John work as a security guard job 27 hours and as a landscaper 33 hours.

5 0
3 years ago
How can you simplify 24 to 96 ​
Nezavi [6.7K]

Step-by-step explanation:

Reduce 24/96 to lowest terms

Find the GCD (or HCF) of numerator and denominator. GCD of 24 and 96 is 24.

24 ÷ 2496 ÷ 24.

Reduced fraction: 14. Therefore, 24/96 simplified to lowest terms is 1/4.

7 0
3 years ago
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Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all
Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that p = 0.95

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

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2 years ago
Is x=-1 a solution of: -4-4x&lt;-x-2
vodka [1.7K]

Answer:

yes it's a solution. I think. I don't really know this

5 0
3 years ago
Solve the equation<br> 12 + 0.35x = 20.05
zubka84 [21]
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7 0
3 years ago
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