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madreJ [45]
2 years ago
13

The formula for distance is given as distance = speed x time. Use the formula to find:

Mathematics
1 answer:
MakcuM [25]2 years ago
8 0

❥\Large\pmb {\underline {\tt Answer}}

Given :-

  • Time = 5 hours
  • Speed = 120 km/h

To find:

  • Distance

We know:-

  • Distance = Speed × Time
  • Distance = 5 × 120
  • Distance = 600km

Required Answer :-

600 km

<u>━━━━━━━━━━━━━━━━━━</u>

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18<br> 8<br> 13<br> 7<br> Find the area of the white granite area in the picture above.
GaryK [48]

Answer: 178

Step-by-step explanation:

18x13

234 area of white granite

8x7

56 area of blue granite

234-56 to find the area of the white granite

8 0
3 years ago
How do I solve this and what kind of formula is it?
soldier1979 [14.2K]

Answer:

160

Step-by-step explanation:

The measure of an arc is always twice the degree of the corresponding angle inside the circle. For example, the measure of arc DC is just double the measure of angle DOC; angle DOC is 44 degrees, so arc DC must be 88 degrees.

Angle COB is 80 degrees, so arc CB is 160 degrees.

5 0
3 years ago
What is (4x^3+27x^2+45x)/9x
kvasek [131]

x^{4}Answer:

3x^{3} + x^{2} - 2x times 1

3 0
3 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
2 years ago
Can you answer THIS one in the picture form
iVinArrow [24]

Answer:

this is what I got

Step-by-step explanation:

4 0
3 years ago
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