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kumpel [21]
3 years ago
14

NEED HELP ASAP

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

When solving an equation with an absolute value term, you make two separate equations ans solve for x:

Equation 1: |4x-3|-5 = 4

1st add 5 to both sides:

|4x-3| = 9

Remove the absolute value term and make two equations:

4x-3 = 9 and 4x - 3 = -9

Solving for x you get X = 3 and x = -1.5

When you replace x with those values in the original equation the statement is true so those are two solutions.

Do the same thing for equation 2:

|2x+3| +8 = 3

Subtract 8 from both sides:

|2x+3| = -5

Remove the absolute value term and make two equations:

2x +3 = -5

2x+3 = 5

Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.

The answer is:

C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

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Andrea opened a bank account for her daughter Hannah, with a deposit of $ 1,750 . The account will earn 2% simple interest annua
Feliz [49]

Answer:

84 months

Step-by-step explanation:

I × 100 = P × R × T

I = interest = $245

P = principal = $1750

R = rate = 2%

T = time(in years) = ??

245 × 100 = 1750 × 2 × T

24500 = 3500T

24500/3500 = T

7 = T

To convert the time to month:

7 × 12 = 84 months

7 0
3 years ago
Factor.<br> 4z² – 8z - 5
Nataly [62]

Answer: z = -1/2 = -0.500

z = 5/2 = 2.500

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (22z2 -  8z) -  5  = 0  

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  4z2-8z-5  

The first term is,  4z2  its coefficient is  4 .

The middle term is,  -8z  its coefficient is  -8 .

The last term, "the constant", is  -5  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -5 = -20  

Step-2 : Find two factors of  -20  whose sum equals the coefficient of the middle term, which is   -8 .

     -20    +    1    =    -19  

     -10    +    2    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -10  and  2  

                    4z2 - 10z + 2z - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2z • (2z-5)

             Add up the last 2 terms, pulling out common factors :

                    1 • (2z-5)

Step-5 : Add up the four terms of step 4 :

                   (2z+1)  •  (2z-5)

            Which is the desired factorization

Equation at the end of step  2  :

 (2z - 5) • (2z + 1)  = 0  

Step  3  :

Theory - Roots of a product :

3.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

3.2      Solve  :    2z-5 = 0  

Add  5  to both sides of the equation :  

                     2z = 5

Divide both sides of the equation by 2:

                    z = 5/2 = 2.500

Solving a Single Variable Equation :

3.3      Solve  :    2z+1 = 0  

Subtract  1  from both sides of the equation :  

                     2z = -1

Divide both sides of the equation by 2:

                    z = -1/2 = -0.500

Supplement : Solving Quadratic Equation Directly

Solving    4z2-8z-5  = 0   directly  

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex :

4.1      Find the Vertex of   y = 4z2-8z-5

For any parabola,Az2+Bz+C,the  z -coordinate of the vertex is given by  -B/(2A) . In our case the  z  coordinate is   1.0000  

Plugging into the parabola formula   1.0000  for  z  we can calculate the  y -coordinate :  

 y = 4.0 * 1.00 * 1.00 - 8.0 * 1.00 - 5.0

or   y = -9.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = 4z2-8z-5

Axis of Symmetry (dashed)  {z}={ 1.00}  

Vertex at  {z,y} = { 1.00,-9.00}  

z -Intercepts (Roots) :

Root 1 at  {z,y} = {-0.50, 0.00}  

Root 2 at  {z,y} = { 2.50, 0.00}  

Solve Quadratic Equation by Completing The Square

4.2     Solving   4z2-8z-5 = 0 by Completing The Square .

Divide both sides of the equation by  4  to have 1 as the coefficient of the first term :

  z2-2z-(5/4) = 0

Add  5/4  to both side of the equation :

  z2-2z = 5/4

Now the clever bit: Take the coefficient of  z , which is  2 , divide by two, giving  1 , and finally square it giving  1  

Add  1  to both sides of the equation :

 On the right hand side we have :

  5/4  +  1    or,  (5/4)+(1/1)  

 The common denominator of the two fractions is  4   Adding  (5/4)+(4/4)  gives  9/4  

 So adding to both sides we finally get :

  z2-2z+1 = 9/4

Adding  1  has completed the left hand side into a perfect square :

  z2-2z+1  =

  (z-1) • (z-1)  =

 (z-1)2

Things which are equal to the same thing are also equal to one another. Since

  z2-2z+1 = 9/4 and

  z2-2z+1 = (z-1)2

then, according to the law of transitivity,

  (z-1)2 = 9/4

We'll refer to this Equation as  Eq. #4.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (z-1)2   is

  (z-1)2/2 =

 (z-1)1 =

  z-1

Now, applying the Square Root Principle to  Eq. #4.2.1  we get:

  z-1 = √ 9/4

Add  1  to both sides to obtain:

  z = 1 + √ 9/4

Since a square root has two values, one positive and the other negative

  z2 - 2z - (5/4) = 0

  has two solutions:

 z = 1 + √ 9/4

  or

 z = 1 - √ 9/4

Note that  √ 9/4 can be written as

 √ 9  / √ 4   which is 3 / 2

Solve Quadratic Equation using the Quadratic Formula

4.3     Solving    4z2-8z-5 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  z  , the solution for   Az2+Bz+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

           - B  ±  √ B2-4AC

 z =   ————————

                     2A

 In our case,  A   =     4

                     B   =    -8

                     C   =   -5

Accordingly,  B2  -  4AC   =

                    64 - (-80) =

                    144

Applying the quadratic formula :

              8 ± √ 144

  z  =    —————

                   8

Can  √ 144 be simplified ?

Yes!   The prime factorization of  144   is

  2•2•2•2•3•3  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 144   =  √ 2•2•2•2•3•3   =2•2•3•√ 1   =

               ±  12 • √ 1   =

               ±  12

So now we are looking at:

          z  =  ( 8 ± 12) / 8

Two real solutions:

z =(8+√144)/8=1+3/2= 2.500

or:

z =(8-√144)/8=1-3/2= -0.500

Two solutions were found :

z = -1/2 = -0.500

z = 5/2 = 2.500

3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
Charra [1.4K]

Answer:

C. O.5s

Step-by-step explanation:

If the wave length is 100m and it goes at a speed of 200m/s then it will only take 0.5 seconds because 100 is half of the speed of 200

6 0
3 years ago
Read 2 more answers
Find the 14th term of the geometric sequence 2, 6, 18,
butalik [34]

The geometric sequence is starting with 2 and multiplying by 3 every time. We can get the rule of this sequence by...

If 2 is a_0, 6 is a_1, 18 is a_2, etc.

a_n=2*3^n

For the 14th term, which is a_13, the value is 2*3^13.

Using a calculator because I'm too lazy to calculate 3^13 sorry, we can get.

3188646

6 0
3 years ago
Someone help me with this please
anzhelika [568]

for question 1

Area of Base B =45×25 = 1125 cm²

perimeter of base P = 2(45+25) = 140 cm

Height = 15 cm

Using the formula

Surface area = 2B + Ph

A = 2×1125 + 140×15= 4350 cm²

Voume = Bh = 1125×15= 16875 cm³

For question 2,

Area of base = 7× 5/2= 17.5 cm²

Perimeter of base = (7+7+7) = 21 cm

Surface area = 2B + Ph

Surface area of prism = 2×17.5+ 21×10 = 245cm²

Volume = Bh = 17.5×10 = 175 cm³

6 0
3 years ago
Read 2 more answers
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