20 with a number minus what will equal 9. ^_^
If you would like to know which of the following steps should be performed to eliminate variable d first, you can find this using the following steps:
equation a: 2c = d - 8 /*(-3)
equation b: c = 3d + 8
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-6c = -3d + 24
c = 3d + 8
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-6c + c = -3d + 24 + 3d + 8
-5c = 32
5c = -32
c = -32/5
<span>The correct result would </span>be: <span>multiply equation a by −3.</span>
“A” is the answer i believe !
hope this helps
This is the future value quadrupled in t years at an annual interest rate of 6.5% compounded daily. We need to find t.
1*(1+0.065/365)^(365t)t=4
take log on both sides,
365t(log(1+0.065/365)=log(4)
=>
365t=log(4)/log(1+0.065/365)
t=(log(4)/log(1+0.065/365))/365
=(1.38629/.000178066)/365
=21.33 years
Check with the rule of 69, applicable to continuous compounding (an approximation to current problem) to double money, it take 69/interest rate in % years.
=69/6.5
=10.62 years
To double twice (quadruple), it takes twice 10.62
=21.24 years, not that far from 21.33 that we got earlier.
